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4 years ago

Can anyone help me with this problem

Mathematics

2 answers:

antiseptic1488 [7]4 years ago

7 0

Sure, fill in x as the numbers on the table, and the correct answer is A

Novay_Z [31]4 years ago

4 0

All you have to do is substitute the x values in the graph into the equation: y=1/2(0-8)
then solve for y
(-4)

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What is the missing coefficient? x2 + 4x + 2x x2 + x please help me

olchik [2.2K]

6
x^2 + 6x since 4x + 2x = 6x

7 0

4 years ago

he gross income of Maurice Vaughn is $785 per week. His deductions are $42.25, FICA tax; $90.33, income tax; 2% state tax; 1% ci

docker41 [41]

Answer:

A. $605.32

Step-by-step explanation:

The state tax, city tax, and retirement fund add to 6% of Vaughn's wages, or ...

... $785 · 6% = $47.10

Then after subtracting all the deductions, Vaughn's take-home pay is ...

... $785 -42.25 -90.33 -47.10 = $605.32 . . . . matches A

3 0

3 years ago

Adult tickets cost 8 dollars students cost 4 of they sold 30more adult tickets as made 840 dollars how many adult tickets were s

g100num [7]

I do not quite understant

6 0

4 years ago

At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper

Korvikt [17]

Answer:

90.67% probability that John finds less than 7 golden sheets of paper

Step-by-step explanation:

For each container, there are only two possible outcomes. Either it contains a golden sheet of paper, or it does not. The probability of a container containing a golden sheet of paper is independent of other containers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper containers.

This means that $p = 0.3$

14 of these containers of paper.

This means that $n = 14$

What is the probability that John finds less than 7 golden sheets of paper?

$P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{14,0}.(0.3)^{0}.(0.7)^{14} = 0.0068$

$P(X = 1) = C_{14,1}.(0.3)^{1}.(0.7)^{13} = 0.0407$

$P(X = 2) = C_{14,2}.(0.3)^{2}.(0.7)^{12} = 0.1134$

$P(X = 3) = C_{14,3}.(0.3)^{3}.(0.7)^{11} = 0.1943$

$P(X = 4) = C_{14,4}.(0.3)^{4}.(0.7)^{10} = 0.2290$

$P(X = 5) = C_{14,5}.(0.3)^{5}.(0.7)^{9} = 0.1963$

$P(X = 6) = C_{14,6}.(0.3)^{6}.(0.7)^{8} = 0.1262$

$P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0068 + 0.0407 + 0.1134 + 0.1943 + 0.2290 + 0.1963 + 0.1262 = 0.9067$

90.67% probability that John finds less than 7 golden sheets of paper

7 0

3 years ago

I need help with geometry/ algebra

Advocard [28]

Step-by-step explanation:

answer is attached as image

6 0

3 years ago