9514 1404 393
Answer:
625 square feet
Step-by-step explanation:
The greatest area of a polygon with a given perimeter is that of a regular polygon. A regular rectangle is one that has all sides the same length -- a square. The side length of a square with 100 ft perimeter is 25 ft. The area of a square with such a side length is
A = (25 ft)² = 625 ft²
The maximum possible area is 625 ft².
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In the attached, x is the length of one side. The area versus side length is plotted. The maximum is seen to be 625 ft² for a side length of 25 ft.
Answer:
52
Step-by-step explanation:
sorry if it's wrong
Answer:
100
Step-by-step explanation:
Answer:
See below:
Step-by-step explanation:
Hello! I hope you are having a nice day!
We can solve this problem in two steps; solving and theory.
I'll go and start off with the theory part!
Theory
We know that in geometry there are many types of triangles that have various different angles. With that, there are a few special triangles that people have made formulas for, one being a 30, 60, and 90 degree triangle.
The theorem states that the hypotenuse is 
, the side opposite to 60 degrees is 
, and the bottom is 
.
Solving
We can solve this problem in a step, we just need to know what the theorem said and implement it here, since we know the values of the sides of the triangle, we can solve it by finding out the opposite side and applying the theorem rules.
If we look at the graph, we can see that the part of the side opp. of 60 degrees is 4, that means that would be double of 4, which is 8.
Therefore your answer would be: 
Cheers!
