I’m not sure how to do this someone explain please

Mathematics

1 answer:

Stels [109]3 years ago

6 0

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Fractional indices pls help

bulgar [2K]

Answer:

Formula used :

(a^m)^n = a^(m×n)
a^m × a^n = a^(m+n)

$27 \times {9}^{3x} = {3}^{k} \\ {3}^{3} \times { {(3}^{2}) }^{3x} = {3}^{k} \\ {3}^{k} = {3}^{3} \times {3}^{(2 \times 3x)} \\ {3}^{k} = {3}^{3} \times {3}^{6x} \\ {3}^{k} = {3}^{(6x + 3)} \\ \boxed{k = 6x + 3}$

<u>k = (6x+3)</u> is the right answer.

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