Question

A solid sphere of radius 42 cm has a total positive charge of 23 µC uniformly distributed throughout its volume. Calculate the magnitude of the electric field at 150 cm from the center of the sphere.

Answer 1

Answer:

Electric field due to uniformly charged sphere is 9.2 x 10⁴ N/C

Explanation:

Given :

Radius of the solid sphere, R = 42 cm = 0.42 m

Total charge on the sphere, Q = 23 μC = 23 x 10⁻⁶ C

Distance of the point from the center of the sphere, r = 150 cm = 1.5 m

Since, r > R, so the point is outside the sphere. Thus, the electric field outside the uniformly charged sphere is determine by the relation:

$E=\frac{kQ}{r^{2} }$

Here k is constant and its value is 9 x 10⁹ N·m²/C².

Substitute the suitable values in the above equation.

$E=\frac{9\times10^{9}\times23\times10^{-6} }{(1.5)^{2} }$

E = 9.2 x 10⁴ N/C