Answer:
// EDU HACK REDDIT EDITON //
if (running == null) {
var running = null; console.log("Program Loading...");
var iframe = document.getElementById("stageFrame");
for (i = 0; i < 1; i++) {
setInterval(function() {
if (running == null) { running = true; console.log('Program Loaded! Enjoy!') }
if (iframe.contentWindow.document.getElementsByClassName('FrameRight') != null) { iframe.contentWindow.document.getElementsByClassName('FrameRight')[0].onclick(); }
if (iframe.contentWindow.document.getElementById("invis-o-div") != null) { iframe.contentWindow.document.getElementById("invis-o-div").remove(); }
},1000);
}
} else {
console.log("Program already running!")
}
Explanation:
Given:
h = 600 m, the height of descent
t = 5 min = 5*60 = 300 s, the time of descent.
Let a = the acceleration of descent., m/s².
Let u = initial velocity of descent, m/s.
Let t = time of descent, s.
The final velocity is v = 0 m/s because the helicopter comes to rest on the ground.
Note that u, v, and a are measured as positive upward.
Then
u + at = v
(u m/s) + (a m/s²)*(t s) = 0
u = - at
u = - 300a (1)
Also,
u*t + (1/2)at² = -h
(um/s)*(t s) + (1/2)(a m/s²)*(t s)² = 600
ut + (1/2)at² = 600 (2)
From (1), obtain
-300a +(1/2)(a)(90000) = -600
44700a = -600
a = - 1.3423 x 10⁻² m/s²
From (1), obtain
u = - 300*(-1.3423 x 10⁻²) = 4.03 m/s
Answer:
The acceleration is 0.0134 m/s² downward.
The initial velocity is 4.0 m/s upward.
As you said, the speed is constant in a vacuum, so the speed does not change, The frequency, on the other hand, decreases by half. The wavelength, λ (lambda), the frequency, v, and the speed of light, c, are related by the equation λν = c. We can see that frequency and wavelength are inversely proportional, so an increase in wavelength has a corresponding decrease in frequency.
when wire is added short Circuit occurs makes bulb 1 and 2 turn off but keeps bulb 3 and 4 on .
