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Zepler [3.9K]
3 years ago
7

What 2 things are recommended in order for you to have a neat graph

Mathematics
1 answer:
Oksana_A [137]3 years ago
6 0

Answer:

use a ruler

or

buy a graph

Step-by-step explanation:

Not the best answer tho... becuase this useless Mod deleted all my answers randomly

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Sdfghjkljhgfdxzs idk
levacccp [35]

Answer:

D

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What are the terms in the expression 6ab +7c-8d +11f
Alisiya [41]
The terms are a b c d andf
7 0
3 years ago
Can U solve this?!<br><br> No Improper answers!
amm1812

Answer:

1

Step-by-step explanation:

multiply and divide(left to right)

=9-9+1

Add and subtract(left to right)

=1

6 0
3 years ago
Read 2 more answers
Urgent math help needed will mark brainliest
iren [92.7K]

Remark

Many calculators have a key that will do this in one step. Mine is one of them. So let's start with the answer and then we'll do it the long way.

9C3 = 84. You put it into your calculator as 9   2nF   nCr 3 =

Solution

\dfrac{9!}{(n - 3)!3!} = \dfrac{9*8*7*6!}{6!*3!}=\dfrac{9*8*7}{6}

3*4*7 = 84 which is what you set out to show.


3 0
3 years ago
What is the value of x ??
ruslelena [56]

Answer:

A

Step-by-step explanation:

The Tangent-Secant Exterior Angle Measure Theorem states that if a tangent and a secant or two tangents/secants intersect outside of a circle, then the measure of the angle formed by them is half of the difference of the measures of its intercepted arcs. Basically, what that means here is that x equals half of the difference of 30\textdegree and the measure of the unlabeled arc.

First, we need to find the measure of the unlabeled arc, since we can't find x without it. We know that the measure of the full arc formed by the circle is 360\textdegree, so the measure of the unlabeled arc must be 360-30-100-100=130\textdegree by the Arc Addition Postulate.

Now, we can find x. Using all of the information known, we can solve for x like this:

\\x=\frac{1}{2} (130\textdegree-30\textdegree)\\=\frac{1}{2} (100\textdegree)\\=50\textdegree

Hope this helps!

5 0
2 years ago
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