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4 years ago

9

(25 POINTS!!)What is the equation of the line that passes through the points (15,9) and (-2,9)?

2 answers:

dsp734 years ago

8 0

$\text{d stands for distance between two points} \\d(A, B)=\sqrt{(\Delta{x})^2+(\Delta{y})^2} \\\text{or simply} \\d(A, B)=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\\text{now put in the data} \\d(A, B)=\sqrt{(-2-15)^2+(9-9)^2} \\d(A, B)=\sqrt{(-17)^2} \\d(A, B)=\boxed{17} \\$

Viktor [21]4 years ago

5 0

Let's use the point-slope formula...

<em>y-y1=m(x-x1) </em>

<em>m is the slope. </em>

<em>y--9=7(x--2) </em>

<em>Subtracting a negative number is the same as adding a positive number... </em>

<em>y+9=7(x+2) </em>

<em>y+9=7x+14 </em>

<em>Let's subtract 9 from both sides... </em>

<em>-9+y+9=7x+14-9 </em>

<em>y=7x+5 </em>

<em>The formula is now in the format of... </em>

<em>y=mx+b </em>

<em>This is known as slope-intercept. </em>

<em>m is the slope. </em>

<em>b is the y-intercept, the value of y when x=0. </em>

<em>Standard formula is... </em>

<em>Ax+By=C </em>

<em>Neither A nor B equal zero. </em>

<em>A is greater than zero. </em>

<em>y=7x+5 </em>

<em>Let's move 7x to the left side of the equation. It becomes negative. </em>

<em>-7x+y=5 </em>

<em>Let's multiply both sides by -1 to render A greater than zero. </em>

<em>-1(-7x+y)=(5)(-1) </em>

<u>7x-y=-5 </u>

<u>This is the equation in standard form.</u>

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$\huge{\boxed{\sf{ ( 3 , 3 ) }}}$

Step-by-step explanation:

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Let the co-ordinates of point B be ( x , y )

A ( -7 , 1 ) $\longrightarrow$ ( x1 , y1 )

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Now,

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Finding the value of x :

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Do cross multiplication

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Hence, The co-ordinates of point B = ( 3 , 3 )

Hope I helped!

Best regards!

~ $\text{ TheAnimeGirl}$

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