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Roman55 [17]
3 years ago
9

(25 POINTS!!)What is the equation of the line that passes through the points (15,9) and (-2,9)?

Mathematics
2 answers:
dsp733 years ago
8 0

\text{d stands for distance between two points} \\d(A, B)=\sqrt{(\Delta{x})^2+(\Delta{y})^2} \\\text{or simply} \\d(A, B)=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\\text{now put in the data} \\d(A, B)=\sqrt{(-2-15)^2+(9-9)^2} \\d(A, B)=\sqrt{(-17)^2} \\d(A, B)=\boxed{17} \\

Viktor [21]3 years ago
5 0

Let's use the point-slope formula...

<em>y-y1=m(x-x1) </em>

<em>m is the slope. </em>

<em>y--9=7(x--2) </em>

<em>Subtracting a negative number is the same as adding a positive number... </em>

<em>y+9=7(x+2) </em>

<em>y+9=7x+14 </em>

<em>Let's subtract 9 from both sides... </em>

<em>-9+y+9=7x+14-9 </em>

<em>y=7x+5 </em>

<em>The formula is now in the format of... </em>

<em>y=mx+b </em>

<em>This is known as slope-intercept. </em>

<em>m is the slope. </em>

<em>b is the y-intercept, the value of y when x=0. </em>

<em>Standard formula is... </em>

<em>Ax+By=C </em>

<em>Neither A nor B equal zero. </em>

<em>A is greater than zero. </em>

<em>y=7x+5 </em>

<em>Let's move 7x to the left side of the equation.  It becomes negative. </em>

<em>-7x+y=5 </em>

<em>Let's multiply both sides by -1 to render A greater than zero. </em>

<em>-1(-7x+y)=(5)(-1) </em>

<u>7x-y=-5 </u>

<u>This is the equation in standard form.</u>

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