Question

A snack bar sells two sizes of drinks. A large drink is $5 and a small drink is $3. In one day, they sold 60 drinks for a total of $220. Write a system of equations to determine how many small and large drinks they sold.
S = number of small drinks
L = number of large drinks
Solve equation for S and L

Answer 1

Answer: 20 large drinks and 40 small drinks

Step-by-step explanation:

From the information given:

L= number of large drinks while S = number of small drinks

Cost of L = $5, while Cost of S = $3

Total number of drinks sold is 60 = $220

Equations:

L + S = 60 .........equation 1

5L + 3S = 220 ..........equation 2

S = 60 - L

Substitute S = 60 - L into equation 2

5L + 3 (60 - L) = 220

5L + 180 - 3L = 220

Combine like terms:

5L - 3L = 220 - 180

2L = 40

Divide both sides by 2:

L = 20 Large drinks

Substitute the value of L into equation 1

20 + S = 60

S = 60 - 20

S = 40 small drinks

Thus, there are 20 large drinks and 40 small drinks.

Answer 2

Answer:

Step-by-step explanation:

Given:

Cost of L = $5

Cost of S = $3

No. of drinks sold = 60 drinks

Total sale = $220

Solution:

L + S = 60 - (1) (multiplying by 3)

5L + 3S = 220 - (2)

(-)3L +(-) 3S = (-)180 - (1)

2L = 40

L = 40 / 2

L = 20 Large drinks

20 + S = 60

S = 60 - 20

S = 40 small drinks

Therefore, 20 large drinks and 40 small drinks

PLEASE MARK ME AS BRAINLIEST