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Ainat [17]
3 years ago
10

Why is renting sometimes considered “throwing money away”?

Mathematics
2 answers:
Leona [35]3 years ago
7 0

Answer:

cuz they ask for an interest with the increase of time

RSB [31]3 years ago
6 0

Step-by-step explanation:

When a person rent's something then the same amount of money has to be paid monthly or the predetermined amount of time. A person may keep paying after the value of the thing is obtained. Then renting becomes a waste.

For example, you are renting a car you pay 1000 dollars every month. And the car costs 10000 dollars. So, the person will be able to buy the car after 10 months. If he rents the car for more than 10 months then he is paying more than the value of the car itself. Then renting is sometimes considered as “throwing money away”.

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What is x equal to in the problem 10+3(x+2)=36? Please show your work.
scZoUnD [109]

Answer:

x = 6 2/3

Step-by-step explanation:

10+3(x+2)=36

10+3x+6=36           Solve inside the parenthesis.

16+3x=36               Combine like terms.

-16       -16                Subtract 16 from both sides.

3x/3=20/3                Divide both sides by 3.

x=6 2/3                     The answer is x= 6 2/3, or 6.66666666666667

5 0
3 years ago
Read 2 more answers
3x+2y=-15 2x=-18 elimination
Sergeeva-Olga [200]

Answer: (-9,6)


Step-by-step explanation:

3x+2y=-15

2x=-18

First solve for x in second equation

2x=-18

2x/2=-18/2

X= -9

Now substitute your x into first equation to find y

3(-9)+2y= -15

-27+2y=-15

2y= -15+27

2y= 12

2y/2=12/2

Y= 6

5 0
3 years ago
dale has a square garden. He adds a 2-foot-wide walkway around his garden. If the total area of the walkway and garden is 196 sq
dem82 [27]
Let the side of the garden alone (without walkway) be x.  
Then the area of the garden alone is x^2.  
The walkway is made up as follows:

1) four rectangles of width 2 feet and length x, and 
 2) four squares, each of area 2^2 square feet.


The total walkway area is thus x^2 + 4(2^2) + 4(x*2).  

We want to find the dimensions of the garden.  To do this, we need to find the value of x.

Let's sum up the garden dimensions and the walkway dimensions:

x^2 + 4(2^2) + 4(x*2) = 196 sq ft

x^2 + 16 + 8x = 196 sq ft

x^2 + 8x - 180 = 0

(x-10(x+18) = 0

x=10 or x=-18.  We must discard x=-18, since the side length can't be negative.  We are left with x = 10 feet.

The garden dimensions are (10 feet)^2, or 100 square feet.


4 0
3 years ago
Use the Newton-Raphson method to find the root of the equation f(x) = In(3x) + 5x2, using an initial guess of x = 0.5 and a stop
xxMikexx [17]

Answer with explanation:

The equation which we have to solve by Newton-Raphson Method is,

 f(x)=log (3 x) +5 x²

f'(x)=\frac{1}{3x}+10 x

Initial Guess =0.5

Formula to find Iteration by Newton-Raphson method

  x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\\\\x_{1}=x_{0}-\frac{f(x_{0})}{f'(x_{0})}\\\\ x_{1}=0.5-\frac{\log(1.5)+1.25}{\frac{1}{1.5}+10 \times 0.5}\\\\x_{1}=0.5- \frac{0.1760+1.25}{0.67+5}\\\\x_{1}=0.5-\frac{1.426}{5.67}\\\\x_{1}=0.5-0.25149\\\\x_{1}=0.248

x_{2}=0.248-\frac{\log(0.744)+0.30752}{\frac{1}{0.744}+10 \times 0.248}\\\\x_{2}=0.248- \frac{-0.128+0.30752}{1.35+2.48}\\\\x_{2}=0.248-\frac{0.17952}{3.83}\\\\x_{2}=0.248-0.0468\\\\x_{2}=0.2012

x_{3}=0.2012-\frac{\log(0.6036)+0.2024072}{\frac{1}{0.6036}+10 \times 0.2012}\\\\x_{3}=0.2012- \frac{-0.2192+0.2025}{1.6567+2.012}\\\\x_{3}=0.2012-\frac{-0.0167}{3.6687}\\\\x_{3}=0.2012+0.0045\\\\x_{3}=0.2057

x_{4}=0.2057-\frac{\log(0.6171)+0.21156}{\frac{1}{0.6171}+10 \times 0.2057}\\\\x_{4}=0.2057- \frac{-0.2096+0.21156}{1.6204+2.057}\\\\x_{4}=0.2057-\frac{0.0019}{3.6774}\\\\x_{4}=0.2057-0.0005\\\\x_{4}=0.2052

So, root of the equation =0.205 (Approx)

Approximate relative error

                =\frac{\text{Actual value}}{\text{Given Value}}\\\\=\frac{0.205}{0.5}\\\\=0.41

 Approximate relative error in terms of Percentage

   =0.41 × 100

   = 41 %

7 0
3 years ago
The difference between the square of two numbers is 11. Twice the square of the first number increased by the square of the seco
jeyben [28]

Answer:

Below in bold.

Step-by-step explanation:

x^2 - y^2 = 11

2x^2  + y^2 = 97

From the first equation:

y^2 = x^2 - 11

Substituting in the second equation:

2x^2 + x^2 - 11 = 97

3x^2 = 108

x^2 = 36

x = 6, -6.

Substituting  for x in the first equation:

(6)^2 - y^2 = 11

y^2 = 36 - 11 = 25

y = 5, -5.

6 0
3 years ago
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