19. What you know is that HK+KJ = HJ. If HJ = 25, the sum of the two equations will equal this length.
x-5+5x-12=25 First, combine your like terms. You will end up with 6x-17=25. Add the opposite of -17 to both sides. 6x = 42 Divide both sides by 6. x = 7. Substitute x=7 for your original expression of x-5, 7-5=2
20. (5x-6)/2 = x+6 Multiply each side by 2. 5x-6 = 2x +12 Add 6 to each side 5x = 2x + 18 then subtract 2x from both sides as well. 3x = 18 Finally divide each side by 3. x=6 To find the length of the remaining segment, substitute this value into (5x-6)/2. This results in each side equaling a distance of 12.
21. On the number line, the distance of FG is 16 units. If the distance of FP is 1/4 of FG, you would simply divide 16 by 4. The distance of FP is 4 and P lies at 8 on your number line.
23. The distance of SP is x+4 and ST=4x. Since P is the midpoint, you only have one half of the line as x+4, if you were to double it, you would find that 2x+8 = 4x. Balance and solve for x, subtract 2x from both sides. 8=2x Divide each side by 4, 8/4 = 4x/4 resulting in x=2. If ST equals 4x, substitute and solve, 4(2) = 8
If the smallest rectangle has a length of 8 meters, and a perimeter of 24 meters then its width is given by:
We can conclude that the width is half of the length for both rectangles. Therefore, the width of the larger rectangle, with a perimeter of 30 meters, is:
