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erica [24]
2 years ago
15

Help with 19,20,21,23 please i don't understand geometry at all

Mathematics
1 answer:
Murrr4er [49]2 years ago
8 0
19.  What you know is that HK+KJ = HJ.  If HJ = 25, the sum of the two equations will equal this length.  

x-5+5x-12=25  First, combine your like terms.  You will end up with 6x-17=25.  Add the opposite of -17 to both sides.  6x = 42  Divide both sides by 6.  x = 7.  Substitute x=7 for your original expression of x-5, 7-5=2

20.  (5x-6)/2 = x+6  Multiply each side by 2.  5x-6 = 2x +12  Add 6 to each side 5x = 2x + 18 then subtract 2x from both sides as well.  3x = 18 Finally divide each side by 3.  x=6   To find the length of the remaining segment, substitute this value into (5x-6)/2.  This results in each side equaling a distance of 12.

21.  On the number line, the distance of FG is 16 units.  If the distance of FP is 1/4 of FG, you would simply divide 16 by 4.  The distance of FP is 4 and P lies at 8 on your number line.

23. The distance of SP is x+4 and ST=4x.  Since P is the midpoint, you only have one half of the line as x+4, if you were to double it, you would find that 2x+8 = 4x.  Balance and solve for x, subtract 2x from both sides. 8=2x  Divide each side by 4, 8/4 = 4x/4 resulting in x=2.  If ST equals 4x, substitute and solve, 4(2) = 8
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Answer:

D:Spring A is 3 m longer than spring B because 15 – 12 = 3.

Step-by-step explanation:

In this question, you should remember the Hooke's Law in physics.

The Hooke's Law simply explains that the extension that occurs on a spring is directly proportional to the load applied on it.

The mathematical expression for this law is

F=-kx

where;

F= force applied on the spring

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The question will need you to calculate the extension on the springs A and B then compare the values obtained.

<u>In spring A</u>

Force, F=60N and spring constant ,k=4 N/m

To find the extension x apply the expression;

F=-kx\\\\60=-4*x\\\\60=-4x\\\\\frac{60}{-4} =\frac{-4x}{-4} \\\\\\-15=x

Here the spring extension is 15 m

<u>In spring B</u>

Force, F=60N and spring constant , k=5N/m

To find the extension x apply the same expression

F=-kx\\\\60=-5*x\\\\60=-5x\\\\\\\frac{60}{-5} =\frac{-5x}{-5} \\\\\\-12=x

Here the extension on the spring is 12 m

<u>Compare</u>

The extension on spring A is 3 m longer than that in spring B because when you subtract the value of spring B from that in spring A you get 3m

=15m-12m=3m

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