We have that
<span>Log3 a/3
</span>Rewrite log3(a/3) using the change of base <span>formula
we know that
</span>The change of base rule can be used if a and b are greater than 0 and not equal to 1, and x is greater than 0<span>.
</span>so
loga(x)=<span>logb(x)/<span>logb<span>(a)
</span></span></span>Substitute in values for the variables in the change of base <span>formula
</span>
in this problem
b=10
a=3
x=a/3
log3(a/3)=[log (a/3)]/[log (3)]
the answer is
[log (a/3)]/[log (3)]
Sin hacon se no se mon anynayo si bor ni ka thu
Solve for y in the first equation.
y = 4x + 6
Substitute <span>4x + 6 into the second equation.
-5x - (</span><span>4x + 6) = 21
Distribute
-5x - 4x - 6 = 21
Combine like terms
-9x = 27
Divide both sides by -9
x = -3
Substitute back into first equation
-4(-3) + y = 6
Solve for y
y = -6</span>
