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2 years ago

-3(5x-9) pls tell me

Mathematics

2 answers:

Elena-2011 [213]2 years ago

8 0

-15x + 27 is the answer

nirvana33 [79]2 years ago

4 0

-15x+27 :))))))) good luck

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Principal $400 Rate 5% time 1 year

zheka24 [161]

Answer:400 multiplied by 5 percent then later multiplied by one, Answer: 20$

Step-by-step explanation:

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2 years ago

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X and y vary inversely and x=50 when y=5 find y when x=10 what is k?

Kisachek [45]

Answer:

Part A)

1) $k=250$

2) $y=25$

Part B)

1) $k=7$

2) $y=84$

Step-by-step explanation:

Part 1) x and y vary inversely and x=50 when y=5 find y when x=10 what is k?

we know that

A relationship between two variables, x, and y, represent an inverse variation if it can be expressed in the form $y*x=k$ or $y=k/x$

step 1

Find the value of k

x=50 when y=5

substitute the values

$y*x=k$ ------> $5*50=k$ -----> $k=250$

The equation is equal to

$y*x=250$ or $y=250/x$

step 2

Find y when x=10

substitute the value of x in the equation and solve for y

$y*(10)=250$

$y=250/10=25$

Part B) x and y vary directly and x=6 when y=42 find k what is y when x=12

we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form $y/x=k$ or $y=kx$

step 1

Find the value of k

x=6 when y=42

substitute the values

$y/x=k$ ------> $42/6=k$ -----> $k=7$

The equation is equal to

$y/x=7$ or $y=7x$

step 2

Find y when x=12

substitute the value of x in the equation and solve for y

$y=7(12)=84$

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3 years ago

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Anna007 [38]

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Step-by-step explanation:

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3 years ago

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Tia performed an experiment where she flipped a coin 200 times. The coin landed heads up 92 times and tails up 108 times. Which

11111nata11111 [884]

only the first statement is true - it is the experimental probability. the rest is incorrect: the ratio is not the number of trials; the theoretical probability should be 0.5 (for unbiased coins); ratio never represents a number of occurences.

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3 years ago

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Make sure to SHOW WORK

attashe74 [19]

9/4=2.25
2.25-1= 1.25

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2 years ago

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