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Reil [10]
3 years ago
12

Which transformation should be applied to the graph of the function y = cot(x) to obtain the graph of the function

Mathematics
1 answer:
kifflom [539]3 years ago
4 0
Trying to get this answer is quite difficult!
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What is the value of x in the equation 1/2x-3/4=3/8-5/8x?
Vladimir [108]

Answer:

x = 1

Step-by-step explanation:

1/2x - 3/4 = 3/8 - 5/8x

The LCD is 8. Lets change every fraction to a denominator of 8.

4/8x - 6/8 = 3/8 - 5/8x

Now multiply both sides by 8.

4x - 6 = 3 - 5x

Add 5x to both sides. Add 6 to both sides.

9x = 9

Divide both sides by 9.

x = 1

7 0
3 years ago
Read 2 more answers
Please help I'm not very good at math and i don't really understand what's going on
solniwko [45]

Answer:

The amount left after each friend got $46.

Step-by-step explanation:

Any time you see R1 in bus stop method division, it just means remainder. So dividing 93 dollars between 2 friends gives them both 46 dollars, with one left over!

Hope this helps :)

8 0
3 years ago
Can someone help me with this question?<br><br><br><br>Which function is a linear function?
Murrr4er [49]

Answer:

e

Step-by-step explanation:

5 0
3 years ago
If the area of a circular pool is 300 square yards, what is its radius?
elixir [45]

Answer:

<h2>radius = 9.77 yards</h2>

Step-by-step explanation:

Since the pool is circular

Area of a circle = πr²

where

r is the radius

From the question

Area = 300 square yards

To find the radius substitute the value of the area into the above formula and solve for the radius

That's

300 = πr²

Divide both sides by π

We have

{r}^{2}  =  \frac{300}{\pi}

Find the square root of both sides

That's

r =  \sqrt{ \frac{300}{\pi} }

r = 9.7720502

We have the final answer as

<h3>radius = 9.77 yards</h3>

Hope this helps you

4 0
3 years ago
Identify the initial amount a and the decay factor b in the exponential function. y equals 5 times 0.5 superscript x
Ber [7]
\bf \qquad \textit{Amount for Exponential Decay}&#10;\\\\&#10;A=a(b)^x\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;a=\textit{initial amount}\\&#10;b=\textit{decay factor}\\&#10;x=\textit{elapsed time}\\&#10;\end{cases}&#10;\\\\\\&#10;y=\stackrel{a}{5}(\stackrel{b}{0.5})^x
7 0
3 years ago
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