3 years ago

What is the 50th term of the arithmetic sequence having u(subscript)1 = -2 and d = 5

Mathematics

1 answer:

OLga [1]3 years ago

8 0

Answer:

243

Step-by-step explanation:

The general term for this arithmetic sequence is:

a(n) = -2 + 5(n - 1).

Then a(50) = -2 + 5(49) = 243

Other answers ; 0.5,2^-1

8 0

3 years ago

Aaaajsnsajdnjsadnjandja'

alekssr [168]

Answer:

wkkeek

Step-by-step explanation:

99992ndndnddke

4 0

3 years ago

Read 2 more answers

Whats the powerpoint equation to 86.4

astraxan [27]

Answer:

26 (:

Hope this helps

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

How to solve this linear equation step by step please

mote1985 [20]

$\bf \cfrac{3}{c^2-4c}-\cfrac{9}{2c^2+3c}=\cfrac{2}{2c^2-5c-12}\\\\\\ 
\begin{cases}
c^2-4c=&c(c-4)\\
2c^2+3c=&c(2c+3)\\\\
2c^2-5c-12=
&(2c+3)(c-4)
\end{cases}\\\\
-------------------------------\\\\
\textit{therefore, our LCD for the \underline{left-side} will have to be }\underline{c(c-4)(2c+3)}\\\\
-------------------------------\\\\$

$\bf \cfrac{3}{c(c-4)}-\cfrac{9}{c(2c+3)}=\cfrac{2}{(2c+3)(c-4)}
\\\\\\
\cfrac{3(2c+3)-9(c-4)}{c(c-4)(2c+3)}=\cfrac{2}{(2c+3)(c-4)}
\\\\\\
\cfrac{6c+9-(9c-36)}{c(c-4)(2c+3)}=\cfrac{2}{(2c+3)(c-4)}
\\\\\\
\cfrac{6c+9-9c+36}{1}=\cfrac{2[c(c-4)(2c+3)]}{(2c+3)(c-4)}
\\\\\\
-3c+45=2c\implies 45=5c\implies \cfrac{45}{5}=c\implies 9=c$

7 0

3 years ago