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3 years ago

9. Find P(rolling 1 or 5) with one number cube.

Mathematics

1 answer:

marta [7]3 years ago

6 0

Answer:

1/3

Step-by-step explanation:

There are 6 possible outcomes when rolling 1 die

1,2,3,4,5,6

P ( 1 or 5) = number of times 1 or 5 happens / total outcomes

= 2/ 6

= 1/3

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What is the distance between (1,-5) and (-3,6)

Wewaii [24]

Answer:

$\large\boxed{\sqrt{137}\approx11.7}$

Step-by-step explanation:

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have two points (1, -5) and (-3, 6). substitute:

$d=\sqrt{(-3-1)^2+(6-(-5))^2}=\sqrt{(-4)^2+11^2}=\sqrt{16+121}=\sqrt{137}$

4 0

3 years ago

Consider the numbers √27 and √39.

kobusy [5.1K]

√27 = 5.2 (to 1 dp)
√39 = 6.2 (to 1 dp)
A. √39 is greater.
B. 6 is the only whole number between the two.
Hope this helped :)

3 0

3 years ago

A parachutists rate during the freefall reaches 189 km/h. What is the rate in meters per second? At this rate how many meters wi

Lera25 [3.4K]

1 km = 1000m
1 hr = 3600 s

189 km/h
189 * 1000 / 3600 m/s
189*5/18 m/s
945/18 m/s
315/6 m/s
105/2 m/s
52.5 m/s

in 10 s
52.5*10
525 m

3 0

2 years ago

Find the values of x and y

zhuklara [117]

You can use a tangent:

$tangent=\dfrac{opposite}{adjacent}$

We have opposite = 17 and adjacent = x.

$\tan30^o=\dfrac{\sqrt3}{3}$

substitute:

$\dfrac{17}{x}=\dfrac{\sqrt3}{3}$ cross multiply

$x\sqrt3=(3)(17)$ multiply both sides by √3

$x(\sqrt3)(\sqrt3)=51\sqrt3$

$3x=51\sqrt3$ divide both sides by 3

$x=17\sqrt3$

Use the Pythagorean theorem:

$y^2=(17\sqrt3)^2+17^2\\\\y^2=289(\sqrt3)^2+289\\\\y^2=289\cdot3+289\\\\y^2=867+289\\\\y^2=1156\to y=\sqrt{1156}\\\\y=34$

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Other method.

$30^o-60^o-90^o$ triangle.

The sides are in the ratio $1:2:\sqrt3\to17:y:x$

Therefore

$17:(2\cdot17):(17\sqrt3)\to17:34:17\sqrt3\to x=34,\ y=17\sqrt3$

4 0

3 years ago

NEED HELP NOW 100 POINTS WILL MARK BRAINLIEST ANSWER!!!

gayaneshka [121]

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6 0

3 years ago

Read 2 more answers