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olasank [31]
3 years ago
8

A model rocket is fired from the ground at time t=0, and it’s height is given in cm by the formula h=-490t^2 +1470t where t is m

easured in seconds.
Write an equation to find when the height of the rocket is 980 cm.


Solve the equation by factoring.


Explain why there are two solutions to this problem.
Mathematics
1 answer:
Natali [406]3 years ago
4 0

Step-by-step explanation:

h = -490t² + 1470t

When h = 980:

980 = -490t² + 1470t

Simplifying:

0 = -490t² + 1470t - 980

0 = t² - 3t + 2

Factoring:

0 = (t - 1) (t - 2)

t = 1, 2

There are two solutions because the rocket first reaches the height of 980 cm as it's going up at 1 second, then it reaches that height again as it's coming down at 2 seconds.

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A type of bacteria has a very high exponential growth rate of 80% every hour. If there are 10 bacteria, determine how many will
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<h3>There are 189 bacteria in 5 hours</h3><h3>There are 13382588 bacteria in 1 day</h3><h3>There are 10(1.8)^{168} bacteria in 1 week</h3>

<em><u>Solution:</u></em>

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A type of bacteria has a very high exponential growth rate of 80% every hour

There are 10 bacteria

<em><u>The increasing function is given as:</u></em>

y = a(1+r)^t

Where,

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From given,

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<em><u>Determine how many will be in 5 hours</u></em>

Substitute t = 5

y = 10(1 + 0.8)^5\\\\y = 10(1.8)^5\\\\y = 10 \times 18.89568\\\\y \approx 188.96

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Thus, there are 189 bacteria in 5 hours

<em><u>Determine how many will be in 1 day ?</u></em>

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Substitute t = 24

y = 10(1 + 0.8)^{24}\\\\y = 10(1.8)^{24}\\\\y = 10 \times 1338258.84\\\\y = 13382588.45\\\\y \approx 13382588

Thus, there are 13382588 bacteria in 1 day

<em><u>Determine how many will be in 1 week</u></em>

1 week = 168

Substitute t = 168

y = 10(1 + 0.8)^{168}\\\\y = 10(1.8)^{168}

Thus there are 10(1.8)^{168} bacteria in 1 week

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