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Ede4ka [16]
3 years ago
8

3y^2-16y-12 factor by grouping

Mathematics
1 answer:
NISA [10]3 years ago
5 0
(y - 6)(3y + 2)

Take the y^2 coefficient 3 and multiply the constant by it, to get y^2 - 16y - 36

Find two numbers that multiply to 36 and add to -16, which are -18 and 2. Use these numbers as the second term in the polynomial, to get (y - 18)(y + 2).

Divide the numbers by the original coefficient
3, and if there’s a fraction, move the denominator to the coefficient of the variable.

(y - 18/3)(y + 2/3) —> (y - 6)(3y + 2)
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6 0
3 years ago
6x^2+x-12 in factored form
pychu [463]
6x²+x-12

the first thing we need to do is find 2 numbers that add up to equal the middle term (1) but multiply together to get a product of -72 (-12*6)

two numbers that would fit this is 9 and -8
so now we placed 9x and -8x in place of the middle term

6x²+9x-8x-12

now we look for whats common between the first two numbers and divide them out

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now we do the same with the last two numbers

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notice how the numbers in brackets are the same (2x+3)
we will keep (2x+3) and then combine the numbers on the outside

once we do that you should get an answer of 

(3x-4)(2x+3)

hope this helped!


5 0
3 years ago
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Step-by-step explanation:

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