Since we need a point that divides K-->J into two segments in a 1:3 ratio, let's flip it to a 3:1 ratio in the J-->K direction. That means that this point is 3/(3+1) = 3/4 of the way up line JK.
Let's take 3/4 of the x of K (plus the 1 for the x of J):
3/4×(9 - 1) + 1 (because the beginning ofvthe line, at J, has an x of 1)...
3/4×(8) + 1 = 6 + 1 = 7
Therefore the answer is C) 7
Answer:
First off if you want this answered make sure it's clear when your multiplying or using X
It has line symmetry and rotational symmetry, so A is the answer, hope this helps
Answer:
It does not exist.
Step-by-step explanation:
If we divide the second term by the first, 3rd by the 2nd and the 4th by the 3rd we get a constant result 4/3.
So this is a Geometric Series with common ratio r = 4/3 and a1 = 1/3.
As the common ratio is greater than 1 the series diverges ( continues to get bigger) so there is no sum to infinity. It just goes on getting bigger and bigger without bounds.
In Quadrant I, sin(sin^-1(x)) = x.
The appropriate choice is
B.
