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3 years ago

Ricardo weigh 2pounds

Mathematics

1 answer:

IrinaVladis [17]3 years ago

7 0

Answer:

I think that you are missing parts of your question as it is just a statement

Step-by-step explanation:

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How do find a number out of a percent

Nana76 [90]

You only have the % and you need the number. For example i got a 87% on my Math test what is that as a decimal? The answer is 0.87 because you move the decimal ahead 2 numbers.

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3 years ago

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Classwork Let's tick (V) the correct answer.

Fynjy0 [20]

Answer:

Option i

Step-by-step explanation:

The given expression is , 5x² - 3xy .

We can clearly see that there are two terms in the expression , 5x² and 3xy .

Therefore option (i) is correct .

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3 years ago

Mr. Murphy has an old coin that has 10 sides. If it's shape it's a polygon how many angles does the old coin have

shepuryov [24]

Epretty sure it's 10 angles

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3 years ago

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One side of a triangle is 3 times the second side. The third side is 17 feet longer than the second side. The perimeter of a

Nadya [2.5K]

Answer:

Step-by-step explanation:

lets have one side =a

P=3a+a+(17+a)=52

P=5a+17=52

5a=52-17

5a=35

a=7

second side=21

third side=24

3 0

3 years ago

Pyramid A has a triangular base where each side measures 4 units and a volume of 36 cubic units. Pyramid B has the same height,

omeli [17]

Answer:

The volume of pyramid B is 81 cubic units

Step-by-step explanation:

Given

Pyramid A

$s = 4$ -- base sides

$V = 36$ -- Volume

Pyramid B

$s = 6$ --- base sides

Required

Determine the volume of pyramid B [Missing from the question]

From the question, we understand that both pyramids are equilateral triangular pyramids.

The volume is calculated as:

$V = \frac{1}{3} * B * h$

Where B represents the area of the base equilateral triangle, and it is calculated as:

$B = \frac{1}{2} * s^2 * sin(60)$

Where s represents the side lengths

First, we calculate the height of pyramid A

For Pyramid A, the base area is:

$B = \frac{1}{2} * s^2 * sin(60)$

$B = \frac{1}{2} * 4^2 * \frac{\sqrt 3}{2}$

$B = \frac{1}{2} * 16 * \frac{\sqrt 3}{2}$

$B = 4\sqrt 3$

The height is calculated from:

$V = \frac{1}{3} * B * h$

This gives:

$36 = \frac{1}{3} * 4\sqrt 3 * h$

Make h the subject

$h = \frac{3 * 36}{4\sqrt 3}$

$h = \frac{3 * 9}{\sqrt 3}$

$h = \frac{27}{\sqrt 3}$

To calculate the volume of pyramid B, we make use of:

$V = \frac{1}{3} * B * h$

Since the heights of both pyramids are the same, we can make use of:

$h = \frac{27}{\sqrt 3}$

The base area B, is then calculated as:

$B = \frac{1}{2} * s^2 * sin(60)$

Where

$s = 6$

So:

$B = \frac{1}{2} * 6^2 * sin(60)$

$B = \frac{1}{2} * 36 * \frac{\sqrt 3}{2}$

$B = 9\sqrt 3$

So:

$V = \frac{1}{3} * B * h$

Where

$B = 9\sqrt 3$ and $h = \frac{27}{\sqrt 3}$

$V = \frac{1}{3} * 9\sqrt 3 * \frac{27}{\sqrt 3}$

$V = \frac{1}{3} * 9 * 27$

$V = 81$

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3 years ago

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