Answer:
The population proportion is estimated to be with 99% confidence within the interval (0.1238, 0.2012).
Step-by-step explanation:
The formula for estimating the population proportion by a confidence interval is given by:
Where:
is the sample's proportion of success, which in this case is the people that regularly lie during surveys,
is the critical value needed to find the tails of distribution related to the confidence level,
is the sample's size.
<u>First</u> we compute the value:
<u>Next</u> we find the z-score at any z-distribution table or app (in this case i've used StatKey):
Now we can replace in the formula with the obtained values to compute the confidence interval:
Answer
Step-by-step explanation:
One solution :
x = -1/3 = -0.333
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
-5*(3*x+1)+4*x-(10*x+2)=0
Step by step solution :
Step 1 :
Equation at the end of step 1 :
((0 - 5 • (3x + 1)) + 4x) - (10x + 2) = 0
Step 2 :
Step 3 :
Pulling out like terms :
3.1 Pull out like factors :
-21x - 7 = -7 • (3x + 1)
Equation at the end of step 3 :
-7 • (3x + 1) = 0
Step 4 :
Equations which are never true :
4.1 Solve : -7 = 0
n=2
8+8(8-n)=40+8n (distribute 8 through the parenthesis)
8+64-8n=40-8n (add the numbers)
<em>72-</em>8n=40+8n (move the variable to the left side and change its sign)
<em>72</em><em>-</em>8n+8n=40
-8n+8n=40<em>-72</em> (connect like terms)
-16n = -32 (divide both sides by -16)
<u><em>n=2</em></u>
Answer:D
Step-by-step explanation:
In d the x’s cancel out so y is not a function of x anymore!
