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Naya [18.7K]
3 years ago
15

How do you find the area of a cone?

Mathematics
1 answer:
Gala2k [10]3 years ago
8 0
To find of a cone

\pi \: r \sqrt{r}^{2}  + h {}^{2}
hope this help you
may i got a brainliest please
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Which is another way to write this equation?
icang [17]
6/8 can be simplified to 3/4. Therefore the answer is C. 20 X 3/4
8 0
3 years ago
Read 2 more answers
How to make 20/12 into a whole number and a fraction?
Ludmilka [50]

Hey there,

The whole number(or mixed fraction) would be: 1 2/3

The improper fraction would be: 5/3

:)

6 0
4 years ago
Read 2 more answers
How do I solve systems of equations? I was absent and the test is next week!
MrRa [10]
Well, there are three different ways to solve systems of equations:
a) Graphing
b) Substitution
c) Elimination

Graphing:
If your system of equations are written in slope-intercept form (y=mx+b "m" being the slope and "b" being the y-intercept) its quite easy.
The y-intercept is pretty much where your line touches the y-axis so if your first equation is: y=3x-2 then you will put your first point on (0,-2). Then from that point you follow the slope. if the slope is 3 then you'll rise 3 and run 1 (go three times up and one to the right and put your point right there) till you feel you have enough points to make a line. You do the same process with your second equation.

Substitution:
This is best when you have a system of equations in which an equation tells you what x or y are equal to. For example: if I have "4x+2=y" and "2y+3x= 26" you can "replace" your "2y" with the equation "4x+2=y" which gives you a brand new equation: " 2(4x+2)+3x=26". To solve this you do the distributive property and link like terms which gives you the equation "11x+4=26". Then you solve like a normal equation, isolating x and then you'll get the value of x (in this case x=2). Now you go to the first equation "4x+2=y" and replace "x" to its value (in this case it's 2) and you get y (in this example, y=10).

Elimination:
I think this one is one of the easiest methods. Let's say my systems of equations is "5x-6y=-32" & "3x+6y=48". If you take a look at y's coefficients, you see they are the same. So you can "cancel them out" like this:
      5x-6y=-32
   + 3x+6y=48
-----------------------
     8x=16  <-------- when you get this, you can solve like a normal equation
       x=2

Also, if you have, for example:
2x+6y=190 & 2x+3y=130
You can solve this by: canceling x or multiplying the second equation by 2 and canceling y.
I'm gonna show you how to do the second way (multiplying and canceling y)
My second equation is "2x+3y=130". To get an equivalent equation, I just have to multiply the whole equation by any number. If I want to cancel y, then I have to multiply by 2.
So "2x+3y=130" turns into "4x+6y=260"
Now you follow the same procedure as before:
            2x+6y=190
       -    4x+6y=260
-------------------------------
      -2x= -70
       2x=70--------> x=35
Then you pretty much follow the substitution method by replacing "x" to "35" in one of the equations.

        Hope this covers all you missed in class. If you have any questions you can comment them here or message me. :D Good luck in your exam!!!

5 0
3 years ago
A) What is the domain and range of the graph? (Use the equations editor or explain)
riadik2000 [5.3K]

The domain: -5 < x ≤ 1 and the range: -3 ≤ y ≤ 1 is a function. b)

No, the vertical line crosses the graph in more than one place, therefore, the relation shown is a function.

<h3>What is the domain and range of the function?</h3>

The domain of a function is defined as the set of all the possible input values that are valid for the given function.

The range of a function is defined as the set of all the possible output values that are valid for the given function.

The domain of a relation is the set of values of the independent variable for a defined function.

The domain is the horizontal extent of the graph.

The range of a relation is the set of values of the dependent variable for a defined function.

The range is the vertical extent of the graph.

The vertical line can intersect the graph in at most one place.

a)

This graph extends from x > -5 to x = 1.

The domain

 -5 < x ≤ 1   ------   (-5, 1] in interval notation

This graph extends from y = -3 to y = 1.

The left side of the graph does not include the point (-5, 1), but the right side includes the point (1, 1).

y = 1 is one of the output values of the relation.

The range

 -3 ≤ y ≤ 1 . . . . . . . . [-3, 1] in interval notation

b)

No, the vertical line crosses the graph in more than one place, therefore, the relation shown is a function.

Learn more about the domain and range of the function:

brainly.com/question/2264373

#SPJ1

8 0
3 years ago
Find the zero of the following function.<br>f(x)=x³-7x²+4x+12 <br><br><br><br><br><br><br><br>​
chubhunter [2.5K]

Answer:

Step-by-step explanation:

Hello, we can notice that f(-1)=0 so (x+1) is a factor and we can write.

f(x)=(x+1)(x^2-8x +12)\\\\=(x+1)(x-6)(x-2)

The sum of the zeros is 8=6+2 and the product is 12=6*2

So the zeroes are 2, 6, -1

thanks

6 0
4 years ago
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