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Free_Kalibri [48]
2 years ago
14

Which negative angle is equivalent to a 65° angle?

Mathematics
2 answers:
notsponge [240]2 years ago
5 0

Answer:

C

Step-by-step explanation:

took the test it is the correct answer :)

umka2103 [35]2 years ago
4 0

Answer:

-295

Step-by-step explanation:

A p e x

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Which unit of measure would be appropriate for the volumeof a sphere with the radius of 2 meters
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Meters cubed or m³ or cubic metrrs
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Given: ABCD is a trapezoid, AC ⊥ CD AB = CD, AC=the square root of 75 , AB = 5 Find: AABCD
Ugo [173]

In this attached picture according to the conditions of the problem we have an isosceles trapezoid and since we know that legs are equal (AD=BC=5 cm), we have to calculate bases and height in order to find the area. Working with the triangle BCD, we apply Pythagoras theorem and find that CD = \sqrt{75+25} = 10 cm. Since BDC is a right triangle, applying theorem for the area of triangles, we find that \frac{1}{2} * BF =  \frac{1}{2} * 5 * \sqrt{75} and BF= 0.5\sqrt{75}. Since ABCD is an isosceles trapezoid, triangles ADE and BFC are congruent with Angle Side Angle theorem. Then, DE=FC and with the help of Pythagoras theorem, DE=FC=2.5 cm. Then, AB=EF=5 cm and the area of the trapezoid is  A= BF *  \frac{AB+CD}{2} = 0.5  \sqrt{75}  * \frac{5+10}{2} = 18.75 \sqrt{3}   cm^{2}

3 0
3 years ago
In circle Z, what is m∠2?
garik1379 [7]

Answer:

In a circle, interior angles that are not inscribed or central can be found using the formula < = larger arc + smaller arc / 2. So, in order to find <2, the formula would be <2 = 147 + 133 / 2, so 140.

3 0
3 years ago
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Find the equation of the tangent line to the curve <br> 2exy=x+y at (0,2).
DiKsa [7]

Answer:

The equation of the tangent line to the curve

3 x - y = 2

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given function  = f(x,y) = 2e^{xy} -x-y=0   ...(i)

Differentiating equation (i) with respective to 'x' , we get

2 e^{xy} \frac{d}{d x} (x y) -1 -\frac{dy}{dx} =0

apply  formula

\frac{d}{dx} (UV) = UV^{l} +V U^{l}

<u><em>step(ii):-</em></u>

⇒   2 e^{xy} (x(\frac{d}{d x} ( y))+y(1)) -1 -\frac{dy}{dx} =0

⇒ 2 e^{xy} (x(\frac{d}{d x} ( y))+ 2e^{xy} y(1)) -1 -\frac{dy}{dx} =0

Taking common d y/d x

(2 e^{xy} (x) -1)\frac{dy}{dx} =1- 2e^{x y} y(1))

\frac{dy}{dx} =\frac{1- 2e^{x y} y(1))}{(2 e^{xy} (x) -1)}

put At (0,2)

\frac{dy}{dx} =\frac{1- 2e^{0} 2(1))}{(2 e^{0} (0) -1)}=\frac{1-4}{-1} =3

slope of the curve m = 3

<u><em>Step(iii)</em></u>:-

The equation of the tangent line to the curve

y-y_{1} =m(x-x_{1} )

y - 2 = 3 ( x - 0 )

3 x - y = 2

<u><em>Final answer:-</em></u>

The equation of the tangent line to the curve

3 x - y = 2

8 0
2 years ago
Select the tables that show a proportional relationship between x and y.
stealth61 [152]

Answer:

The table in blue

Step-by-step explanation:

8 0
2 years ago
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