Answer: He had 14 more touchdowns than he did fumbles.
Step-by-step explanation:
Step 1. Ok, so we need to see how many times 9 will divide into 18.
18/9=2.
Step 2. So now that we know that 9 goes into 18 two times and we know he has two fumbles for every 9 touchdowns we can multiply 2 by 2 to find out how man fumbles he had.
2*2=4
Step 3. Now to find out how many more touchdowns than fumbles he had we need to subtract his fumbles from his touchdowns.
18-4= 14. So, now we know he had 14 more touchdowns than he did fumbles.
Hope this helps!
Answer: 3 x 13 ?
Step-by-step explanation:
Answer:
the probability is 2/9
Step-by-step explanation:
Assuming the coins are randomly selected, the probability of pulling a dime first is the number of dimes (4) divided by the total number of coins (10).
p(dime first) = 4/10 = 2/5
Then, having drawn a dime, there are 9 coins left, of which 5 are nickels. The probability of randomly choosing a nickel is 5/9.
The joint probability of these two events occurring sequentially is the product of their probabilities:
p(dime then nickel) = (2/5)×(5/9) = 2/9
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<em>Alternate solution</em>
You can go at this another way. You can list all the pairs of coins that can be drawn. There are 90 of them: 10 first coins and, for each of those, 9 coins that can be chosen second. Of these 90 possibilities, there are 4 dimes that can be chosen first, and 5 nickels that can be chosen second, for a total of 20 possible dime-nickel choices out of the 90 total possible outcomes.
p(dime/nickel) = 20/90 = 2/9
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