The 'scale' of the map is a ratio (or a fraction).
It's <em>(length on the map) / (distance in the real world)</em> .
Different maps have different scales, but the scale is normally the same
everywhere on the same map. So no matter <em>where</em> it is on the map, or <em>how </em>
<em>long</em> the distance is on the map, the ratio is always the <em>same number</em> on <em>that</em>
<em>map</em>.
On this particular map in this question, the ratio is (3.5 inches) / (210 miles) .
Any other measurement on the same map has the same ratio ... and what do
you have when you have equal ratios ?? That's right ! A proportion ! !
The other measurement has the ratio (1.75 inches) / (X miles) , and <u>THAT</u>
fraction is equal to the other one.
(1.75) / ( X ) = (3.5) / (210)
Cross-multiply in the proportion: (1.75 times 210) = (3.5 times X).
Can you find 'X' now ?
Hint: Divide both sides of that equation by 3.5 .
Answer:
The number of hours spend by Diana at the pool that week is 1.6
Step-by-step explanation:
Given as :
The Time spends by Diana at the pool = 0.8 hours per day
The number of days spend by Diana in one week = 2 days
So, The number of hours spend by Diana in one week = number of days × number of hours spend per day .
or, The number of hours spend by Diana in one week = 2 days × 0.8 hours
= 1.6 hours
Hence The number of hours spend by Diana at the pool that week is 1.6 hours Answer
Answer:
It is expected that linearization beyond age 20 will be use a function whose slope is monotonously decreasing.
Step-by-step explanation:
The linearization of the data by first order polynomials may be reasonable for the set of values of age between ages from 5 to 15 years, but it is inadequate beyond, since the fourth point, located at 
, in growing at a lower slope. It is expected that function will be monotonously decreasing and we need to use models alternative to first order polynomials as either second order polynomic models or exponential models.
Answer:
= −1 ± 17 √8
Step-by-step explanation:
i think, im sorry if this doesn't help...
