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irakobra [83]
3 years ago
9

Solve for X. 11x+10=180

Mathematics
2 answers:
stealth61 [152]3 years ago
8 0
Do you have options ? if not try going with this ⬇

Problem: 11x + 10 = 180

Steps to find the answer ⬇

           11(x) + 100 - 180 = ?
Now add the number to your sides to solve this: 11x-170 =?

Divide by 11 on each of your sides to make it more simpler : 11(x) - 170

  x = 170/11. which can also be called (well, written as a decimal ) ➡15.455 
Ilia_Sergeevich [38]3 years ago
7 0
X = 170/11 
H0P3 It H3LPS :)

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The vertices of quadrilateral MNPQ are M(−3,−2),N(−1,4),P(2,4), and Q(4,−2). Translate quadrilateral MNPQ using the vector ⟨3,−4
muminat

Answer:

see explanation

Step-by-step explanation:

A translation using the vector < 3, - 4 > , means

Add 3 to the x- coordinate and subtract 4 from the y- coordinate, so

M (- 3, - 2 ) → M' (- 3 + 3, - 2 - 4 ) → M' (0, - 6 )

N (- 1, 4 ) → N' (- 1 + 3, 4 - 4 ) → N' (2, 0 )

P (2, 4 ) → P' (2 + 3, 4 - 4 ) → P' (5, 0 )

Q (4, - 2 ) → Q' (4 + 3, - 2 - 4 ) → (7, - 6 )

4 0
3 years ago
consider a sequence of independent tosses of a biased coin at times k=0,1,2,…,n. On each toss, the probability of Heads is p, an
omeli [17]

Answer:

1. p*(1-p)

2. n*p*(1-p)

3. p*(1-p)

4. 0

5. p^2*(1-p)^2

6. 57/64

Step-by-step explanation:

1. Let Ik denote the reward (possibly 0) given at time k, for k∈{1,2,…,n}. Find E[Ik].

E[Ik]=  p*(1-p)

2. Using the answer to part 1, find E[R].

E[R]=  n*p*(1-p)

The variance calculation is more involved because the random variables I1,I2,…,In are not independent. We begin by computing the following values.

3. If k∈{1,2,…,n}, then

E[I2k]= p*(1-p)  

4. If k∈{1,2,…,n−1}, then

E[IkIk+1]=  0

5. If k≥1, ℓ≥2, and k+ℓ≤n, then

E[IkIk+ℓ]=  p^2*(1-p)^2

6. Using the results above, calculate the numerical value of var(R) assuming that p=3/4, n=10.

var(R)= 57/64

5 0
3 years ago
Solve the system of equations y=9x+13 y=2x+48
MakcuM [25]
Both are equal y. So you can set them equal to each other

9x+13=2x+48

Subtract 2x from both sides

7x+13=48
Subtract 13 from both sides

7x= 35

X=5
7 0
4 years ago
How do i do this.
Sonbull [250]
You have to multiply both numbers with the same factor. What I mean, 475/58 gives you 8 R 11. Now let's try this, (475x2=950) and (58x2= 116) so our new numbers are 950/116 which gives us the same answer 8 R 11 ! I hope this helped.. But let's try another one, keep in mind, you can multiply the number by any factor AS LONG AS you multiply them with the SAME factor. So if you multiply 475 by 5, then you have to multiply the 58 by 5 as well. Now let's try, (475x5=2375) and (58x5= 290) therefore, 2375/290 = which gives you 8 R 11 ! I hope I helped . I am a Palestinian student in Palestine in grade 11 and you just brought me back to grade 4 memories ! math is fun when you get it (: good luck
6 0
3 years ago
Karl is purchasing a $205,000 home with a 30-year mortgage at 5.5%. Because he is not making a down payment, PMI in the amount o
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$421,369.20 , I just had this question on Apex.

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