Question

Which of these are quadratic function(s)? (Select all that apply).

Answer 1

A. $y(y+4)-y=6$
$y^2+4y-y-6=0$
$y^2+3y-6=0$

B. $(3x+2)+(6x-1)=0$
$3x+2+6x-1=0$
$9x+1=0$

C. $4b*b=0$
$4b^2=0$

D. $3a-7=2(7a-3)$
$3a-7=14a-6$
$11a+1=0$

The answers: A, C

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Answer 2

Answer:

A function is called Quadratic if ,it consist of  only one variable, maximum of three terms, and highest degree of the variable  in that Polynomial is 2.

Let start from option 1

A. y *(y+4) - y =6

y² + 4 y - y -6=0

y²+3 y -6=0

This is Quadratic Function.

Option B:

3 x +2 + 6 x -1=0

9 x-1=0

Not, Quadratic Function

Option C:

4 b*(b)=0

4 b²=0

This is Quadratic Function.

Option D:

3 a- 7 =2 * (7 a-3)

3 a - 7=14 a - 6

3 a - 14 a = 7 -6

-11 a =1

Not a Quadratic Function.

Option A :  y(y + 4) - y = 6

And, Option C: 4 b (b)=0

are Quadratic Functions.