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Marina CMI [18]
3 years ago
12

Find an equation of the tangent line to the curve y=arccos(x/2) at the point (1,4pi)

Mathematics
1 answer:
marishachu [46]3 years ago
5 0
The derivative of inverse trigonometric identities follow<span> a set of rules. </span>
<span>For </span>arc cos<span> x, the </span>dy/dx is equal to -1/ square root of (1 - x2). 
<span>In this case, we still have 1/2 x inside the angle quantity so we multiply the </span>dy/dx above with 1/2. Hence, y' = is -1<span>/ 2 square root of (1 - x2); x = 1, y' is infinity. this means the line is horizontal. The answer hence is y = 1.</span>
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Two angles that add up to 90° are called SUPPLEMENTARY angles. TRUE OR FALSE
svet-max [94.6K]

Answer:

This is FALSE. Two supplementary angles add up to 180 degrees.

Step-by-step explanation:

Hope this helped! :-)

3 0
3 years ago
If x plus one upon X equal to 11 find the value of x square + 1 upon x square
zubka84 [21]
119 <answer (check the solution in above pic)


hey friend i hope this answer is helpful


marl as brainliest if i deserve

6 0
3 years ago
(a) Suppose you have 9 gold coins that look identical, but you also know one (and only one) of them is counterfeit. The counterf
alisha [4.7K]

Answer:

Step-by-step explanation:

You can split the coins into 3 groups, each of them has 3 coins. Weigh group 1 vs group 2, if one is lighter, that group has the fake coin. If both groups weigh the same, then group 3 has the fake coin.

Continue to split the group that has the fake coin into 3 groups, each group has 1 coin. Now apply the same procedure and we can identify the fake coin.

Total of scale usage is 2

b) if you have 3^n coins then you can apply the same approach and find the fake coin with just n steps. By splitting up to 3 groups each step, after each step you should be able to narrow down your suspected coin by 3 times.

Step 1: you narrow down to group of \frac{3^n}{3} = 3^{n-1} coins

Step 2: you narrow down to group of \frac{3^{n-1}}{3} = 3^{n-2} coins

Step 3: you narrow down to group of \frac{3^{n-2}}{3} = 3^{n-3} coins

...

Step n: Step 1: you narrow down to group of 3^{n-n} = 3^0 = 1coin

8 0
3 years ago
If a system of linear equations has an infinite number of solutions, what do you know about the graph of the system?
exis [7]
The answer is B because they never pass through each other therefore it has infinite possibilities
7 0
2 years ago
Find the limit of the function algebraically. limit as x approaches negative nine of quantity x squared minus eighty one divided
scoray [572]
Let me express the equation clearly:

lim x→-9  (x²-81)/(x+9)

Initially, we solve this by substituting x=-9 to the equation. 

((-9)²-81)/(-9+9) = 0/0

The term 0/0 is undefined. This means that the solution is not see on the number line because it is imaginary. Other undefined terms are N/0 (where N is any number), 0⁰, 0×∞, ∞-∞, 1^∞ and ∞/∞. One way to solve this is by applying L'Hopitals Rule. This can be done by differentiating the numerator and denominator of the fraction independently. Then, you can already substitute the x=-9.

(2x-0)/(1+0) = 2x = 2(-9) = -18

The other easy way is to substitute x=-8.999 to the original equation. Note that the term x→-9 means that x only approaches to -9. Thus, you substitute a number that is very close to -9. Substituting x=-8.999

((-8.999)²-81)/(-8.999+9) = -18

7 0
3 years ago
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