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4 years ago

11

The values of x and y vary directly and one pair of values are given. Write an equation that relates x and y. x=-4,y=6

1 answer:

makkiz [27]4 years ago

5 0

Answer:

Step-by-step explanation:

If two variables are directly proportional, it means that an increase in the value of one variable would cause a corresponding increase in the other variable. Also, a decrease in the value of one variable would cause a corresponding decrease in the other variable.

Given that x varies directly with y, if we introduce a constant of proportionality, k, the expression becomes

x = ky

If x = - 4 when y = 6, then

- 4 = 6k

k = - 4/6 = - 2/3

Therefore, the equation that relates x and y is

x = -2y/3

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Which of the following is an example of a proper fraction?<br>a.3/4<br>b.4/3<br>c.7/6<br>d.4/4

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The answer is A. 3/4.

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4 years ago

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A family has four children. If the genders of these children are listed in the order they are born, there are sixteen possible o

Agata [3.3K]

Answer:

$\begin{array}{cccccc}X&0&1&2&3&4\\Pr&\dfrac{1}{16}&\dfrac{1}{4}&\dfrac{3}{8}&\dfrac{1}{4}&\dfrac{1}{16}\end{array}$

Step-by-step explanation:

A family has four children. If the genders of these children are listed in the order they are born, there are sixteen possible outcomes: BBBB, BBBG, BBGB, BGBB, GBBB, BGBG, GBGB, BGGB, GBBG, BBGG, GGBB, BGGG, GBGG, GGBG, GGGB, and GGGG.

Let X represent the number of children that are girls. Then

1. When X=0, there is one possible outcome BBBB. So

$Pr(X=0)=\dfrac{1}{16}$

2. When X=1, then there are 4 possible outcomes GBBB, BGBB, BBGB, BBBG, so

$Pr(X=1)=\dfrac{4}{16}=\dfrac{1}{4}$

3. When X=2, then there are 6 possible outcomes BGBG, GBGB, BGGB, GBBG, BBGG, GGBB, so

$Pr(X=2)=\dfrac{6}{16}=\dfrac{3}{8}$

4. When X=3, then there are 4 possible outcomes GGGB, GGBG, GBGG, BGGG, so

$Pr(X=3)=\dfrac{4}{16}=\dfrac{1}{4}$

5. When X=4, then there is one possible outcome GGGG, so

$Pr(X=4)=\dfrac{1}{16}$

Now, the probability distribution table is

$\begin{array}{cccccc}X&0&1&2&3&4\\Pr&\dfrac{1}{16}&\dfrac{1}{4}&\dfrac{3}{8}&\dfrac{1}{4}&\dfrac{1}{16}\end{array}$

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4 years ago

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Which statements about the composite figure are true? Check all that apply.

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Answer:

A)The composite figure consists of two rectangular pyramids.

D)The total volume is 45 units³.

Step-by-step explanation:

Hope it helps...

Have a great day!!

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3 years ago

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Translate to a quadratic equation, then solve using the quadratic formula. The length of a rectangular air filter is 3 inches l

balu736 [363]

Answer:

Width of the rectangle = 17 inches

Length of the rectangle = 31 inches

Step-by-step explanation:

Let w be the width of the rectangle.

Given:

Width of the rectangle = w

Length of the rectangle = 2w - 3

Area of the rectangle $=527\ inches^{2}$

Solution:

We know that the area of the rectangle.

$Area\ of\ rectangle = length\times width$

$w(2w-3)=527$

$2w^{2}-3w-527=0$

Now, we first find the root of the above equation.

Use quadratic formula with $a=2, b=-3, c=-527$ .

$t=\frac{-b\pm \sqrt{(b)^{2}-4ac}}{2a}$

Put a, b and c value in above equation.

$w=\frac{-(-3)\pm \sqrt{(-3)^{2}-4(2)(-527)}}{2(2)}$

$w=\frac{3\pm \sqrt{9+8\times 527}}{4}$

$w=\frac{3\pm \sqrt{9+4216}}{4}$

$w=\frac{3\pm \sqrt{4225}}{4}$

$w=\frac{3\pm 65}{4}$

For positive sign

$w=\frac{68}{4}$

w = 17 inches

So, width of the rectangle is 17 inches.

Length of the rectangle.

$Length = 2\times w-3$

$Length = 2\times 17-3$

$Length = 34-3$

Length = 31 inches

So, length of the rectangle is 31 inches.

Therefore, width and length of the rectangle is 17 inches and 31 inches.

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If you were in a canoe traveling downstream at 5.5 mph and your wheel falls off how many boxes of waffles does it take to re-shi

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Not sure to be honest

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