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3 years ago

URGENT PLEASE HELP!!!!

Mathematics

1 answer:

beks73 [17]3 years ago

6 0

Answer:

Step-by-step explanation:

hope it helps

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Change 15/4 to mixed number

MA_775_DIABLO [31]

15/4

how many times does 4 go into 15 without going over.....that would be 3 times....so 3 is ur whole number. 3 * 4 = 12......15 - 12 = 3...and 3 is ur numerator....the denominator stays the same

so ur answer is : 3 3/4

7 0

3 years ago

An item is priced at $13.26. If the sales tax is 5%, what does the item cost including sales tax?

mezya [45]

Answer:

13.92$

Step-by-step explanation:

13.26 times .05 (sales tax)

.66 + 13.26 = 13.92

7 0

3 years ago

Read 2 more answers

Write as an exponent with the base of b:<br> <img src="https://tex.z-dn.net/?f=b%5E%7Bn%7D%20b%5E%7B5%7D" id="TexFormula1" title

goldfiish [28.3K]

B^n+5
When multiplying exponents the numbers are added

4 0

3 years ago

A researcher wishes to estimate, with 99% confidence, the population proportion of adults who think the president of their co

scoray [572]

Answer:

a. n=4148

b. n=3909

c. The sample size is smaller if a known proportion from prior study is used. The difference in sample sizes is 239

Step-by-step explanation:

a. For sample where no preliminary estimate is given, the minimum sample size is calculated using the formula:

$n=p(1-p)(\frac{z}{ME})^2$

Where:

$ME=$ Margin of error
$p=$ is the assumed proportion

#Let p=0.5, substitute in the formula to solve for n:

$n=0.5(1-0.5)\times (2.576/0.02)^2\\\\=4147.36\approx 4148$

Hence, the minimum sample size is 4148

b. If given a preliminary estimate p=0.38, we use the same formula but substitute p with the given value:

$n=p(1-p)(z/ME)^2\\\\=0.38(1-0.38)(2.576/0.02)^2\\\\=3908.47\approx3909$

Hence, the minimum sample size is 3909

c. Comparing the sample sizes from a and b:

$n_{0.5}>n_{0.38}\\\\n_{0.5}-n_{0.38}=4148-3909=239$

Hence, the actual sample size is smaller for a known proportion from prior a prior study.

8 0

3 years ago

I need help "quick

Ivahew [28]

A is the correct choose.could you make me brainlets answer please

3 0

3 years ago