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2 years ago

Alvin at 1/3 of a pizza for dinner and took 1/6 of it for lunch the next day . How much pizza does he have left

2 answers:

7 0

1/3=2/6

So he ate 2/6ths of the pizza and now there is 4/6ths left.

He took 1/6ths with him for lunch so 4/6-1/6=3/6
You can simplify 3/6 to 1/2

He was 1/2 of the pizza left.

VMariaS [17]2 years ago

4 0

The answer to this is 1/3

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What is the value of this expression? (−2)^5

dalvyx [7]

Answer:

-32

Step-by-step explanation:

=(-2)^5

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2 years ago

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2 years ago

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Viefleur [7K]

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2 years ago

What decimal is equal to 32%?

AlexFokin [52]

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5 0

3 years ago

Read 2 more answers

A research company desires to know the mean consumption of meat per week among people over age 40. A sample of 610 people over a

Papessa [141]

Answer: $(3.0,\ 3.2)$

Step-by-step explanation:

Confidence interval for population mean is given by :-

$\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$ (1)

, where $\overline{x}$ = Sample mean

$z_{\alpha/2}$ = Critical z-value

$\sigma$ = Population standard deviation.

n= Sample size.

As per given , we have

n= 610

$\sigma=1.1$

$\overline{x}=3.1$

Significance level for 85% confidence : $\alpha=1-0.85=0.15$

By z-table critical two tailed z-value : $z_{\alpha/2}=z_{0.075}=1.44$

Put all values in (1) , we get

$3.1\pm 1.44\dfrac{1.1}{\sqrt{610}}$

$3.1\pm 1.44\dfrac{1.1}{24.698}$

$3.1\pm 0.064$

$=(3.1-0.064,\ 3.1+0.064)=(3.036,\ 3.164)\approx(3.0,\ 3.2)$

Hence, the 85% confidence interval for the mean consumption of meat among people over age 40. = $(3.0,\ 3.2)$

5 0

3 years ago