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NARA [144]
4 years ago
8

Please help me with this !

Mathematics
1 answer:
Softa [21]4 years ago
5 0
1: 5.65
2: 8.48
3: 8
4: 6.24
5: 5.2
6: 8.66
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5r+8=2r solve the equation for r
lianna [129]
I think it is −2.666666666666667 but i’m not sure!
8 0
3 years ago
Brainliest goes to whoever answers correctly try to show work ONLY if you can also if you want more points answer my other quest
Tresset [83]

Answer:

Hi, there the answer will D. (-3,-4)

Step-by-step explanation:

If we see the pattern LOOK AT THE X VALUE

WE ALREADY HAVE

12,3,2,5,-8.

THAT'S MEANS YOU CAN HAVE THE SAME X VALUE SO I PICKED D BECAUSE THERE IS NO -3 IN THE PATTERN

Hope this helps :)

6 0
3 years ago
How to write in number form and answer the sum of two times x and one is at least 11
bazaltina [42]
Sum= addition
times= multiplication
at least= ≥

"At least" means the left side of the equation cannot be any less than 11. The left side will be at least/at minimum 11.

2x + 1 ≥ 11
subtract 1 from both sides

2x ≥ 10
divide both sides by 2

x ≥ 5


ANSWER: x ≥ 5; x is greater than or equal to (or "at least") 5

Hope this helps! :)
4 0
3 years ago
Which is the ordered pair
Pani-rosa [81]
Consider the point (-6,1):-
y  = 1 , x = -6 
substituting in the inequality:-
1 >= 1/3 * -6 + 4
1 > 2   which is not true so its not A 

Do same process for the other 3 choices
7 0
3 years ago
4/5 ÷ 7/30 please hellllpppp
Softa [21]

Answer:

\frac{24}{7} or 3\frac{3}{7}

Step-by-step explanation:

\frac{4}{5}\div \frac{7}{30}

Step 1: Apply the fraction rule: \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}

=\frac{4}{5}\times \frac{30}{7}

Step 2: Cross-cancel common factor: 5

=\frac{4}{1}\times \frac{6}{7}

Step 3: Multiply fractions: \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}

=\frac{4\times \:6}{1\times \:7}

Step 4: Multiply the numbers: 4\times \:6=24

=\frac{24}{1\times \:7}

Step 5: Multiply the numbers: 1\times \:7=7

=\frac{24}{7}

Therefore, the answer is \frac{24}{7} or in the simplified form; 3\frac{3}{7}

8 0
3 years ago
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