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2 years ago

Consider y=(x+3)^2-1

Mathematics

1 answer:

Rom4ik [11]2 years ago

7 0

The coefficient of x^2 is positive so it will have a minimum value

Its B

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Daca a/3=7/10 calculati 100a

likoan [24]

A/3=7/10
21=10a
a=2.1
100a=100*2.1=210

6 0

3 years ago

Lee has a jar of 100 pennies. She adds groups of 10 pennies to the jar. She adds 5 groups. What numbers does she say?

Alenkinab [10]

150 pennies in the jar .

4 0

2 years ago

Which equation represents a line perpendicular to the line shown on the graph?

Vadim26 [7]

Answer:

See description below.

Step-by-step explanation:

To choose the correct equation, find the slope of the line on the graph. Identify two points on the line. Then subtract to find their rate of change using the slope formula.

$m=\frac{y_2-y_1}{x_2-x_1}$

When you know the slope, find the negative reciprocal. For example, if the slope is 2/1 then the negative reciprocal is -1/2. This is the slope of a perpendicular line to a line with slope 2. Choose the equation which has this same slope.

Example:

y = 2x -1

y= -1/2 +5

4 0

3 years ago

The numbers of teams remaining in each round of a single-elimination tennis tournament represent a geometric sequence where an i

Anit [1.1K]

Answer:

$a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}$

Step-by-step explanation:

We are given the following in the question:

The numbers of teams remaining in each round follows a geometric sequence.

Let a be the first the of the geometric sequence and r be the common ration.

The $n^{th}$ term of geometric sequence is given by:

$a_n = ar^{n-1}$

$a_4 = 16 = ar^3\\a_6 = 4 = ar^5$

Dividing the two equations, we get,

$\dfrac{16}{4} = \dfrac{ar^3}{ar^5}\\\\4}=\dfrac{1}{r^2}\\\\\Rightarrow r^2 = \dfrac{1}{4}\\\Rightarrow r = \dfrac{1}{2}$

the first term can be calculated as:

$16=a(\dfrac{1}{2})^3\\\\a = 16\times 6\\a = 128$

Thus, the required geometric sequence is

$a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}$

4 0

3 years ago

Please Help!!! Will give brainliest

qaws [65]

36 cm^2

Step-by-step explanation:

Small window

Length: 2cm

Width: 2cm

Area: 4 cm^2

Big window

Length: 4cm

Width: 3cm

Area: 12 cm^2

Total area of the windows:

(Area of 4 small windows + area of 1 big window)

(4 cm^2 x 4 + 12cm^2)

= 28 cm^2

Above window (approx.)

Rectangle

Length: 3cm

Width: 2cm

Area: 6 cm^2

Triangle

Base: 1cm

Height: 1cm

Area: 2 x 0.5 cm^2 = 1 cm^2

Square (between the triangles)

Length: 1cm

Width: 1cm

Area: 1 cm^2

= 8 cm^2

TOTAL AREA OF ALL WINDOWS

= AREA OF 4 WINDOWS + AREA OF BIG WINDOW + AREA OF ABOVE WINDOW

= 16 cm^2 + 12 cm^2 + 8 cm^2

I hope I made the explanations clear enough to make it easier for you to understand!

8 0

1 year ago