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r-ruslan [8.4K]
3 years ago
13

How is the quotient of 8,552 and 16 determined using an area model?

Mathematics
1 answer:
Alina [70]3 years ago
8 0

Answer:

It is 88

Step-by-step explanation:

It is so because fist you do all the math leading it to be 88.

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I need a. Correct answer I will mark brainliest
Otrada [13]

Answer:

Option (A)

Step-by-step explanation:

By satisfying the equation of a function 'f' by each coordinates given in the options we can get the point which lies on the graph of f(x) = 2\times (5)^x

Option (A). (1, 10)

f(1) = 2\times (5)^1

10 = 10

True.

Therefore, point (1, 10) lies on the graph.

Option (B). (0, 10)

f(0) = 2\times 5^0

10 = 2

Not true.

Therefore, point (0, 10) doesn't lie on the graph.

Option (C). (10, 1)

f(10) = 2\times 5^{10}

1 = 19531250

Not true.

Therefore, point (10, 1) doesn't lie on the graph.

Option (D). (0, 0)

f(0) = 2\times 5^0

0 = 2

Not True.

Point (0, 0) doesn't lie on the graph.

Option (A) will be the answer.

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3 years ago
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Molodets [167]
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4 0
3 years ago
Factoring the expression 15x+6 using GCF
s344n2d4d5 [400]
The answer is 3(5x+2) i hope this helps you.
3 0
3 years ago
Find the sum of the even integers from 20 to 50.<br><br><br>with solutions please help​
alina1380 [7]

Answer: 560

Step-by-step explanation:

There are [20, 22, 24, 26, 28]: 5 even integers for each ten numbers.

The 20's set can be written as 5*20 + (2+4 + 6 + 8) = 5*20 + (20) = 120

The 30's can be written: 5*30 + 20 = 170

40's: 5*40+20 = 220

50's: 5*50+20 = 270

60's: 5*60+20 = 320

Each set is incremented by 50

We want the sets for 20, 30, and 40, plus the number 50.

(120+170+220+50) = 560

You can also do this in Excel (attached). Set the first cell to 20, the next cell below equal to the cell above plus 2. Then draw the second cell down until you've reached 50. Then sum the cells to arrive at 560.

7 0
2 years ago
Triangle ABC and triangle DEF are similar. What is the measure of side DF?
Marat540 [252]
I am going to say 15 but I am not sure since there is no pic
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3 years ago
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