Answer: 
<u>Step-by-step explanation:</u>
Pythagorean Theorem is: a² + b² = c² , <em>where "c" is the hypotenuse</em>
<em />

Note: 4² + (8√2)² = hypotenuse² → hypotenuse = 12

Note: 12² + opposite² = 20² → opposite = 16

Note: adjacent² + 5² = 6² → adjacent = √11

Note: adjacent² + 7² = (13√2)² → adjacent = 17
(a4-6a+5)-(a4-3a+4a-6)
by expressing like term
a4-a4=0
-6a-(-3a+4a)=-5a
5-(-6)=11
:we have-5a+11
Answer:
are you okay ? that didnt really make sense sorry love
Step-by-step explanation:
Find area of square: 7^2 = 49
Find radius of circle: 7/2=3.5
find area of circle: 3.5^2*3.14=38.465
Remove area of circle from area of square:
49-38.465=10.535 cm^2
Answer A is the correct one :)
Hi. I was unsure of what exactly you wanted from this equation, so here's a quick analysis:
<em>f(x) = 2(x - 3)^2 - 2</em>
<em></em>
Domain: (-∞, ∞)
Range: (-2, ∞)
X-intercepts: (4, 0), (2, 0)
Y-intercept: (0, 16)
Axis of Symmetry: x = 3
Minimum value (vertex): (3, -2)
Standard form: y = 2x^2 - 12x + 16