All categories

3 years ago

The coordinates A(2, 1), B(7, 1), C(2, 4) form what type of polygon?

Mathematics

2 answers:

scoundrel [369]3 years ago

7 0

Answer:

right triangle

Step-by-step explanation:

Digiron [165]3 years ago

6 0

Step-by-step explanation:

$Slope \: of \: AB = \frac{1 - 1}{7 - 2} = \frac{0}{5} = 0 \\ \\ Slope \: of \: BC = \frac{4 - 1}{2 - 7} = \frac{3}{ - 5} = - \frac{3}{ 5} \\ \\ \because \: Slope \: of \: AB \neq \: Slope \: of \: BC \\ \\ \therefore \: given \: points \: are \: non - collinear. \\$

Hence, coordinates A(2, 1), B(7, 1), C(2, 4) form a triangle.

You might be interested in

Find the area of the following shapes: c

Oksanka [162]

Answer:

Step-by-step explanation:

First, you need to find the length of each of the bases of this trapezoid. YZ has length 5-2=3, while XW has length 8-1=7. The average of these is 5, meaning that since the height of this trapezoid is 5-1=4, the area is 4*5=20. Hope this helps!

4 0

3 years ago

David is a professional ice skater who has skated in 10 competitions. His scores in the competitions are as follows: 204, 310,

anastassius [24]

Answer: 267.7

I just did the math and I got this answer

4 0

3 years ago

You open a savings account and deposit $1,000. After 1 year of earning continuously compounded interest.

Alenkinab [10]

Answer:

Step-by-step explanation:

$1036.66=1000e^{2r}\\ \\ r=(ln(1.03666))/2\\ \\ r=0.018\\ \\ b(x)=1000e^{(0.018x)}\\ \\ b(10)=1000e^{0.18}=\$ 1197.22$

3 0

3 years ago

. Given ????(5, −4) and T(−8,12):

damaskus [11]

Answer:

a) $y=\dfrac{13x}{16}-\dfrac{129}{16}$

b) $y = \dfrac{13x}{16}+ \dfrac{37}{2}$

Step-by-step explanation:

Given two points: $S(5,-4)$ and $T(-8,12)$

Since in both questions,a and b, we're asked to find lines that are perpendicular to ST. So, we'll do that first!

Perpendicular to ST:

the equation of any line is given by: $y = mx + c$ where, m is the slope(also known as gradient), and c is the y-intercept.

to find the perpendicular of ST <u>we first need to find the gradient of ST, using the gradient formula.</u>

$m = \dfrac{y_2 - y_1}{x_2 - x_1}$

the coordinates of S and T can be used here. (it doesn't matter if you choose them in any order: S can be either x_1 and y_1 or x_2 and y_2)

$m = \dfrac{12 - (-4)}{(-8) - 5}$

$m = \dfrac{-16}{13}$

to find the perpendicular of this gradient: we'll use:

$m_1m_2=-1$

both $m_1$ and $m_2$ denote slopes that are perpendicular to each other. So if $m_1 = \dfrac{12 - (-4)}{(-8) - 5}$ , then we can solve for $m_2$ for the slop of ther perpendicular!

$\left(\dfrac{-16}{13}\right)m_2=-1$

$m_2=\dfrac{13}{16}$ :: this is the slope of the perpendicular

a) Line through S and Perpendicular to ST

to find any equation of the line all we need is the slope $m$ and the points $(x,y)$ . And plug into the equation: $(y - y_1) = m(x-x_1)$

side note: you can also use the $y = mx + c$ to find the equation of the line. both of these equations are the same. but I prefer (and also recommend) to use the former equation since the value of 'c' comes out on its own.

$(y - y_1) = m(x-x_1)$

we have the slope of the perpendicular to ST i.e $m=\dfrac{13}{16}$