They are both simple exercises in addition.
The solutions are:
(-65) x (-2) = <em>130</em>
(5j) + (10j) =<em> 15j</em>
STEP 1:
BAGS OF FOUR
find number of bags needed to total 74 apples
= 74 ÷ 4 apples/bag
= 18.5 bags
*must round up to 19 bags because we cannot buy a partial bag
STEP 2:
BAGS OF FOUR
calculate price of 19 bags of 4 apples per bag
= 19 bags * $5/bag
= $95 for 19 bags of 4 apples/bag
STEP 3:
BAGS OF SIX
find number of bags needed to total 74 apples
= 74 ÷ 6 apples per bag
= 12.3333 bags needed
*must round up to 13 bags because we cannot buy a partial bag
STEP 4:
BAGS OF SIX
calculate price of 13 bags of 6 apples per bag
= 13 bags * $7 per bag
= $91 for 13 bags of 6 apples/bag
ANSWER: The smallest cost to buy 74 apples is $91.
Hope this helps! :)
Step-by-step explanation:
met I'd => 86189778400
pas code => g0cg6V
come on g met => spd-mwbz-een
The first number is 170
The second number is 171
Step-by-step explanation:
Let the first number be x^3 and the second number be x^3+1
The sum of the two is 341
X^3+x^3+1=341
2x^3+1=341
Substrate 1 from both sides
2x^3=341-1
