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PilotLPTM [1.2K]

3 years ago

10

What are the factor pairs for 45

1 answer:

riadik2000 [5.3K]3 years ago

7 0

The factored pairs of 45 are:
1 x 45
3 x 15
5 x 9

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What are the dimensions of the matrix?

DerKrebs [107]

Answer:

The dimensions of a matrix are the number of rows × the number of columns of the matrix.

For the example below, the the matrix is 3 × 4.

Explanation:

<em>The dimensions of a matrix</em> is the number of rows × the number of columns of the matrix.

Your matrix is garbled. Thus, to help you I will work with an hypothetical matrix.

Assume the matrix:

$\left[\begin{array}{cccc}1&0&0&0\\2&4&0&3\\0&0&0&9\end{array}\right]$

That matrix has four colums and 3 rows.

For instance, the first colum is:

$\left[\begin{array}{c}1\\2\\0\end{array}\right]$ Thus, it has 4 columns.

And the second row is:

$\left[\begin{array}{cccc}2&4&0&3\end{array}\right]$ Thus, it has 3 rows.

Hence, the matrix is 3 × 4.

The first number is the number of rows and the second number is the number of columnns.

3 0

4 years ago

According to a recent Census Bureau report, 12.7% of Americans live below the poverty level. Suppose you plan to sample at rando

larisa [96]

Answer:

a) $P(X=10)=(100C10)(0.127)^{10} (1-0.127)^{100-10}=0.0928$

b) $P(X \leq 10) = 0.2614$

c) $(1-0.127)^7 (0.127) =0.0491$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=100, p=0.127)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

a. What is the probability that you count exactly 10 in poverty?

For this case we want this probability P(X=10)

$P(X=10)=(100C10)(0.127)^{10} (1-0.127)^{100-10}=0.0928$

b. What is the probability that you count 10 or less in poverty? .2614

For this case we want this probability $P(X=\leq10)$

$P(X\leq10)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)+P(X=6)+P(X=7)+P(X=8)+P(X=9)+P(X=10)$

And we can find the individual probabilities like this:

$P(X=0)=(100C0)(0.127)^{0} (1-0.127)^{100-0}=1.263x10^{-6}$

$P(X=1)=(100C1)(0.127)^{1} (1-0.127)^{100-1}=1.837x10^{-5}$

$P(X=2)=(100C2)(0.127)^{2} (1-0.127)^{100-2}=0.000132$

$P(X=3)=(100C3)(0.127)^{3} (1-0.127)^{100-3}=0.000629$

$P(X=4)=(100C4)(0.127)^{4} (1-0.127)^{100-4}=0.00222$

$P(X=5)=(100C5)(0.127)^{5} (1-0.127)^{100-5}=0.00620$

$P(X=6)=(100C6)(0.127)^{6} (1-0.127)^{100-6}=0.0143$

$P(X=7)=(100C7)(0.127)^{7} (1-0.127)^{100-7}=0.0279$

$P(X=8)=(100C8)(0.127)^{8} (1-0.127)^{100-8}=0.0471$

$P(X=9)=(100C9)(0.127)^{9} (1-0.127)^{100-9}=0.0701$

$P(X=10)=(100C10)(0.127)^{10} (1-0.127)^{100-10}=0.0928$

And then repplacing we got:

$P(X \leq 10) = 0.2614$

c. What is the probability that you start taking the random sample and you find the first person in poverty on the 8th person selected? .0491

For this case we need after 7 people , 1 in poverty so we can find this probability like this:

$(1-0.127)^7 (0.127) =0.0491$

7 0

3 years ago

If a 30-foot tree casts an 18-foot shadow, find the length of the shadow cast by a 27-foot tree.

ipn [44]

Answer:

16.2 foot shadow

Step-by-step explanation:

Let the shadow cast by 27 foot tree be x.

Using ratio and proportions,

18 / 30 = x / 27

(18 x 27) / 30 = x

x = 486 / 30

x = 16.2

8 0

3 years ago

If you apply the changes below to the

Dennis_Churaev [7]

Answer: Step-by-step explanation:

f(x) = (x-7)^2+3

3 0

3 years ago

Please help. Which of the following functions shows an initial amount of $15 and an increase of 35% each year?

IrinaK [193]

Answer:

Step-by-step explanation:

y = 15(1.35)x

6 0

3 years ago