You need to subtract everything to the left side and set it equal to zero. Combine like terms.
Then, the coefficient of x^2 is a, the coefficient of x is b, and the constant term is c.
4x^2 - 5 = 3x + 4
4x^2 - 3x - 5 - 4 = 0
4x^2 - 3x - 9 = 0
a = 4; b = -3; c = -9
Answer:
The coordinates of HF are (1, 4)
Step-by-step explanation:
The parameters of the line are;
The coordinate of the end points are H = (-11, 7), and J = (5, 3)
The ratio by which the point F divides the line = 3:1
The segments in the line are HF, and FJ
Therefore;
The fraction of the length of HJ that is represented by HF = 3/(3 + 1) × HJ = 3/4 × HJ
HF = 3/4 × HJ
Which gives the coordinates of the point F as follows;
Coordinate of F = (-11 +(5 - (-11))×3/4, 7 + (3 - 7)×3/4) = (1, 4)
The coordinates of F are (1, 4)
We check the length of HF, from the equation for the length to of a line to get;
Similarly, we check the length of HJ, to get;
The length of HF = 3·√(17)
The length of HJ = 4·√(17)
Therefore, from HF = 3/4× HJ, we have;
HF = 3/4 × 4·√(17) = 3·√(17)
Therefore, the coordinates of HF are (1, 4)