1/4":1' = 1/4" : 1'= 1:48
So the dimensions of the model are
L=80'/48=960"/48=20"
W=32'/48=384/48=8"
You have 2 options.
I will show you the most efficient one, but later I will tell you the other.
-4x+6y=12
6y=4x+12
y=4/6x+12
y=2/3x+12
This tells us the point (0,12) as 12 is where it meets the y-axis (that is why you add it)
And then using the slope, 2/3 we can get (2,15) (which is up 3, right 2)
Just graph those, I would show you exactly, but I cannot add attachments sadly.
The other way (which I won’t show it all as the results would end out with the same line) is to fill in x, then y, with 0
So -4*0+6y=12 which means x=0 and you are solving for y and -4x+6*0=12 which means y=0 and you are solving for x
Comparing the cost of the car to the deposit, $3,168.00 the amount required to be added to the deposit
$3,168 is the interest
rate = 8%
time = T
principal = 6,600.00
I = ( PRT)/100
T = 100 I/PR
=(100*3168)/(6600*8)
= 6
She should leave the money for six years.
