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tamaranim1 [39]
3 years ago
12

PLEASEEEEEE Which system of equations does not have a real solution? y = x 2 + 3 x - 5 and 4 x + 5y = 20 y = x 2 + 3 x - 5 and x

+ y = -10 y = x 2+ 3 x- 5 and x + y = -9

Mathematics
1 answer:
Delicious77 [7]3 years ago
8 0

Answer:

\Large \boxed{y = x^2  + 3 x - 5 \ \ \mathrm{and} \ \  x + y = -10}

Step-by-step explanation:

y = x² + 3 x - 5 and x + y = -10 are the system of equations that do not have a real solution.

When the two equations are graphed and if they do not intersect, then there are no real solutions for the system of equations.

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Step-by-step explanation:

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