Answer:
What is the question so we can answer
Answer:
The solution to this question is 39
Step-by-step explanation:
Given that :
√(3x+7)+2√(x-8)=0.
√(3x+7)=-2√(x-8) (i)
square of the equation (i)
Then
(√(3x+7))^2=(-2√(x-8))^2
we know that √a*√a=(√a)^2=a So,
(3x+7)=4(x-8)
3x+7=4x-32 //multiply by 4
32+7=4x-3x exchange the value.
39=1x
x=39.
For this case we have that by definition:
A triangle is defined by three lines that are called sides, or by three points called vertices.
We know that:
- <em>The vertices of a triangle are labeled with capital letters.
</em>
- <em>The sides of a triangle are written with lowercase letters.
</em>
- <em>The angles of a triangle are written similarly to the vertices.
</em>
Answer:
The end points of the triangle are called vertices.
They are labeled in capital letters.
If f(x) has an inverse on [a, b], then integrating by parts (take u = f(x) and dv = dx), we can show
Let 
. Compute the inverse:
![f\left(f^{-1}(x)\right) = \sqrt{1 + f^{-1}(x)^3} = x \implies f^{-1}(x) = \sqrt[3]{x^2-1}](https://tex.z-dn.net/?f=f%5Cleft%28f%5E%7B-1%7D%28x%29%5Cright%29%20%3D%20%5Csqrt%7B1%20%2B%20f%5E%7B-1%7D%28x%29%5E3%7D%20%3D%20x%20%5Cimplies%20f%5E%7B-1%7D%28x%29%20%3D%20%5Csqrt%5B3%5D%7Bx%5E2-1%7D)
and we immediately notice that ![f^{-1}(x+1)=\sqrt[3]{x^2+2x}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%2B1%29%3D%5Csqrt%5B3%5D%7Bx%5E2%2B2x%7D)
.
So, we can write the given integral as
Splitting up terms and replacing 
in the first integral, we get
Answer:
Step-by-step explanation:
