Can someone help me with Ratios and Proportions? I’m really struggling for Geometry

The perimeter of a square can represent by 16x + 24. Willa wants to write an equivalent expression for the perimeter that shows

Maslowich

The diagram shows that all the sides of the rectangle are congruent. Since the perimeter all of the sides added up, all you have to do is divide the perimeter by 4.

Therefore, the perimeter, which is 16x + 24, can be divided by 4 to find the length of one side.

16x + 24/4 = length of one side. So, the length of one side is 4x + 6.

Hope this helped!

6 0

3 years ago

HELPPP ASAP PLS

sweet [91]

Answer:

adjacent, linear pair, supplementary

Step-by-step explanation:

adacent because they are angles side by side

linear because the angles create a straight line

supplementary because the angles equal 180 degrees

4 0

3 years ago

4. 10. 4 Test (CST):

kompoz [17]

Based on the value of the annuity, the amount it earns, and the compounding period, the money paid to Nathan each month will be B. $5,840.62.

<h3>How much will Nathan be paid monthly?</h3>

The amount Nathan will be paid is an annuity because it is constant.

First find the monthly interest and the compounding period in months:
= 4.8/12 months

= 0.4%

Number of compounding periods:

= 20 x 12

= 240 months

The monthly payment is:

Present value of annuity = Annuity x ( 1 - (1 + rate) ^ -number of periods) / rate

900,000 = A x ( 1 - (1 + 0.4%)⁻²⁴⁰) / 0.375%

900,000 = A x 154.0932

A = 900,000 / 154.0932

= $5,840.62.

Find out more on the present value of an annuity at brainly.com/question/25792915.

#SPJ1

4 0

2 years ago

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A computer system uses passwords that are six characters, and each character is one of the 26 letters (a–z) or 10 integers (0–9)

Blababa [14]

First of all, since we have 36 characters available per spot (26 letters and 10 digits), and we have 6 spots, we have a total of

$36^6$

possible passwords.

Event A happens if the password starts with either a, e, i, o or u. If we fix the first character, we're left with 36 characters available for each of the remaining 5 spots, leading to a total of

$5\cdot 36^5$

possible passwords.

So, the probability of event A, computed as the ratio between "good" cases and all possible cases, is

$\dfrac{5\cdot 36^5}{36^6}=\dfrac{5}{36}$

Event B works exactly the same, since we're fixing the last spot, leaving 36 characters available for each of the first 5 spots. So, we have

$P(A)=P(B)=\dfrac{5}{36}$

As for the intersection, we want the first character to be a vowel, and the last character to be an even digits. There are 25 passwords satisfying this request:

$axxxx0,\ axxxx2,\ axxxx4,\ axxxx6,\ axxxx8$

$exxxx0,\ exxxx2,\ exxxx4,\ exxxx6,\ exxxx8$

$ixxxx0,\ ixxxx2,\ ixxxx4,\ ixxxx6,\ ixxxx8$

$oaxxxx0,\ oxxxx2,\ oxxxx4,\ oxxxx6,\ oxxxx8$

$uxxxx0,\ uxxxx2,\ uxxxx4,\ uxxxx6,\ uxxxx8$

Where x can be any of the 36 characters.

So, we have 25 cases with 4 vacant slots, leading to a probability of

$P(A\cap B)=\dfrac{25\cdot 36^4}{36^6}=\dfrac{25}{1296}$

Finally, you can compute the probability of the union using the formula

$P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Since we already computed all these quantities.

7 0

3 years ago

The cost of the hiking trip this year is 2/3 of the cost of last year's trip. This year's trip cost $32. Write an equation that

allsm [11]

Answer: (32/2)*3=48

Step-by-step explanation:

In order to find the answer, we must find one third of last year's trip. To do this, we can simply divide the cost of this years trip by two, 32/2=16.

Now if we multiply this this number by 3, 16*3=48, we can see that the total cost of last year's trip was $48.

If we'd like to turn this into one equation, it looks like this: (32/2)*3=48

5 0

3 years ago

Read 2 more answers