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Alenkasestr [34]
3 years ago
5

Can someone help me with Ratios and Proportions? I’m really struggling for Geometry

Mathematics
1 answer:
Leto [7]3 years ago
6 0

Answer:

What do you want to know about?

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g If A and B are disjoint events, with P( A) = 0.20 and P( B) = 0.30. Then P( A and B) is: a. .00 b. .10 c. .50 d. 0.06
Lostsunrise [7]

Answer: A) 0

P(A and B) = 0 when events A and B are disjoint, aka mutually exclusive.

We say that two events are mutually exclusive if they cannot happen at the same time. An example would be flipping a coin to have it land on heads and tails at the same time.

8 0
4 years ago
I need the answers to these or for someone to tell me how to figure it out
Lorico [155]

Answer:

4. Scalene

5. Isosceles

6. Isosceles

7. Equilateral

8. Right

9. Scalene

4 0
3 years ago
Read 2 more answers
SOLVE THIS PLS JSJSXHHX
madam [21]

Step-by-step explanation:

y = ax + b

I see already the result (y = x/10 × 1/6), but let's go in formally.

we have multiple function points to use to officially calculate a and b.

1/6 = a×10 + b

2/3 = a×40 + b

5/6 = a×50 + b

1 2/3 = a×100 + b

let's e.g subtract equation 1 from equation 3.

4/6 = a×40 + 0

a = 4/40 / 6 = 4 / 240 = 1/60

1/6 = 10/60 + b

1/6 = 1/6 + b

b = 0

so, the function is

y = x/60

x = 25

y = 25/60 = 5/12 cups

5 0
3 years ago
What is the percent equivalent of 18/200
Hoochie [10]
The answer is ….. 9%
4 0
3 years ago
Read 2 more answers
A can in the shape of a right cylinder is filled with 10W-40 oil. The weight of 10W-40 oil is 0.857 gram per cubic centimeter. I
Leya [2.2K]
To solve this, we have to find the volume of the cylinder first.  The formula to be used is V =  \pi  r^{2} h

Given:V= ?r= 6cmh= 10cm
Solution:V =  \pi  r^{2} h
V= (3.14)(6cm)^{2} x 10cmV= (3.14)(36cm^{2}) x 10cmV= (113.04cm^{2}) x 10cmV= 1130.4cm^3
Finding the volume of the cylinder, we can now solve what the weight of the oil is.  Using the formula of density, Density = mass/volume, we can derive a formula to get the weight.
Given:Density = 0.857 gm/cm^3Volume = 1130.4 cm^3
Solution:weight = density x volumew= (0.857 gm/cm^3) (1130.4cm^3)w= 968.7528 gm
The weight of the oil is 968.75 gm.
5 0
3 years ago
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