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3 years ago

Which expression is equivalent to

Mathematics

1 answer:

Kruka [31]3 years ago

5 0

Answer:

B) 1/x^2

Step-by-step explanation:

Simplify the following:

x^9/x^11

Hint: | For all exponents, a^n/a^m = a^(n - m). Apply this to x^9/x^11.

Combine powers. x^9/x^11 = x^(9 - 11):

x^(9 - 11)

Hint: | Evaluate 9 - 11.

9 - 11 = -2:

Answer: x^(-2) = 1/(x^2)

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May I please receive help?

BARSIC [14]

Answer: m∠2 = 28°

Step-by-step explanation: Right bro. 1000%

6 0

2 years ago

Read 2 more answers

What is the squat root of 0.64

Vaselesa [24]

<span>sqrt(.64) = sqrt(64/100) = sqrt(64)/sqrt(100) = 8/10 = 4/5 = .8</span>
Your answer is 0.8.

6 0

3 years ago

Bailey can put x houses of his holiday miniature village on each of 7 shelves. He also has 10 houses displayed on his buffet. If

const2013 [10]

Answer:

7x + 10 ≥ 45

Step-by-step explanation:

Given that:

Number of shelves = 7

Number of houses to display on each shelf = x

Number of houses to display = atleast 45 (≥)

Number displayed on buffet = 10

Number displayed on buffet + (number of shelves * number per shelf) ≥ number of houses to display

10 + (7 * x) ≥ 45

7x + 10 ≥ 45

8 0

3 years ago

A pair of equations is shown below.

Ivenika [448]

Answer:

(2,3)

Step-by-step explanation:

desmos is a great graphing app if you ever have another question like that you can put the equations in and see the graphs inputs.

5 0

3 years ago

You do a study of hypnotherapy to determine how effective it is in increasing the number of hours of sleep subjects get each nig

brilliants [131]

Answer:

Confidence interval

$8.98-2.2\frac{1.29}{\sqrt{12}}=8.16$

$8.98+2.2\frac{1.29}{\sqrt{12}}=9.80$

And the margin of error would be:

$ME=2.2\frac{1.29}{\sqrt{12}}=0.819$

Step-by-step explanation:

For this case we have the followig dataset:

DATA: 8.2; 9.1; 7.7; 8.6; 6.9; 11.2; 10.1; 9.9; 8.9; 9.2; 7.5; 10.5

We can calculate the mean and the deviation with the following formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And replacing we got:

$\bar X= 8.98[/tex[tex]s = 1.29$

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=12-1=11$

The Confidence level is 0.95 or 95%, the value of significance is $\alpha=0.05$ and $\alpha/2 =0.025$ , and the critical value would be $t_{\alpha/2}=2.20$

Repplacing the info we got:

$8.98-2.2\frac{1.29}{\sqrt{12}}=8.16$

$8.98+2.2\frac{1.29}{\sqrt{12}}=9.80$ And the margin of error would be:

$ME=2.2\frac{1.29}{\sqrt{12}}=0.819$

7 0

3 years ago