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PIT_PIT [208]
3 years ago
6

What is a cubic polynomial function with zeros 3,3 and -3? show your work.​

Mathematics
1 answer:
Brums [2.3K]3 years ago
4 0

Answer:

Cubic polynomial function with zeros 3,3 and -3 is \mathbf{x^3-3x^2-9x+27=0}

Step-by-step explanation:

We need to find a cubic polynomial function with zeros 3,3 and -3.

If zeros of polynomial are: 3,3,and -3

we can write:

x=3, x=3, x=-3

Or

We can write:

x-3=0, x-3=0, x+3=0

Now, we can write them as:

(x-3)(x-3)(x+3)=0

Multiplying the terms, we can find the polynomial:

(x-3)(x-3)(x+3)=0\\(x(x-3)-3(x-3))(x+3)=0\\(x^2-3x-3x+9)(x+3)=0\\(x^2-6x+9)(x+3)=0\\x(x^2-6x+9)+3(x^2-6x+9)=0\\x^3-6x^2+9x+3x^2-18x+27=0\\x^3-6x^2+3x^2+9x-18x+27=0\\x^3-3x^2-9x+27=0

So, cubic polynomial function with zeros 3,3 and -3 is \mathbf{x^3-3x^2-9x+27=0}

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3 years ago
What is the domain of the function f(x)= x + 1 / x^2 - 6x + 8?
VARVARA [1.3K]
Answer:
all real numbers except 4 and 2

Explanation:
The given function is: 
f(x) = \frac{x+1}{x^2-6x+8}

Domain of the function is defined as the values of x that can be used to substitute in the function.

We know that any fraction cannot have a zero in its denominator. Because if this happens, then the fraction would be undefined.

This means that in the given function, we cannot substitute with any value for x that makes the denominator a zero.

Now, we will get the zeroes of the denominator as follows:
x² - 6x + 8 = 0
(x-4)(x-2) = 0
either x-4 = 0 ...........> x = 4
or x-2 = 0 .............> x = 2

Based on the above, we can substitute with any value for x excluding 4 and 2.

This means that the domain of the function is any real real number except 4 and 2

Hope this helps :)
7 0
3 years ago
Evaluate the summation of 3 times negative 2 to the n minus 1 power, from n equals 1 to 5. A) −93. B) −33. C) 33. D) 93
lions [1.4K]
∑ ( from n = 1 to n =5 ) 3 · ( -2 ) ^( n -1 )
a 1 = 3 · ( -2 ) ^0 = 3
a 2 = 3 · ( - 2 ) = - 6
a 3 = 3 · 4 = 12
a 4 = 3 · ( - 8 ) = - 24
a 5 = 3 · 16 = 48
3 - 6 + 12 - 24 + 48 = 33
Answer: C ) 33
4 0
3 years ago
Read 2 more answers
Help me please. I don't understand this.
navik [9.2K]

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

Apparently, you're being asked to identify the sequence of steps you would use to compute the volume of the pyramid.

It seems to be a good idea to start with the formula for the volume.

Then, recognize that you need to compute B, so make that computation. The area of the base (B) is the product of the base dimensions (14)(12).

Once you have the value of B, then you can put that, along with the value of h, into the original volume formula.

Evaluating it gives the volume in cubic units.

_____

<em>Additional comment</em>

If you're familiar with the pyramid volume formula, you know that you must compute B before you can make use of the formula. That makes the sequence be B=14(12); B=168; V=1/3Bh; V=1/3(168)(7).

However, if you're starting from scratch, it is probably good to begin with the volume formula. That is what tells you that you need to find B in the first place. This is the sequence we show below.

6 0
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Answer:

8cm

Step-by-step explanation:

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