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3 years ago

Solve this 8x-6(3-2x)

Mathematics

2 answers:

BaLLatris [955]3 years ago

8 0

It would be −47 cause 8 * -6 = -48 then (3-2x) = 1 then -48 + 1 = -47 so that’s the answer

marishachu [46]3 years ago

5 0

Answer:

20x−18

Step-by-step explanation:

Apply the distributive property.

8x−6⋅3−6(−2x)8x-6⋅3-6(-2x)

Multiply −6-6 by 33.

8x−18−6(−2x)8x-18-6(-2x)

Multiply −2-2 by −6-6.

8x−18+12x

Add 8x8x and 12x12x.

20x−18

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Whats the input value of f(x)=2x+5

Juli2301 [7.4K]

Answer:

Step-by-step explanation:

f(x)=2x+5

Input: x

Output: f(x)

For i.e:

Input: 1

Output: f(1) = 2(1) + 5 = 2 + 5 = 7

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2 years ago

Find the mean median mode and range. 5, 8, 11, 13, 14, 15

AlexFokin [52]

Answer:

mean-11

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Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Which of the following are solutions to the quadratic equation? Check all that

Firlakuza [10]

Answer:

$\boxed{\sf \ \ \ x=-9 \ \ or \ \ x=2 \ \ \ }$

Step-by-step explanation:

hello,

$2x^2+7x-14=x^2+4\\ 2x^2+7x-14-x^2-4=0\\ x^2+7x-18=0\\x^2-2x+9x-18=0\\ x(x-2)+9(x-2)=0\\ (x+9)(x-2)=0\\ x+9 = 0 \ \text{or} \ x-2=0\\ x = -9 \ \text{or} \ x=2$

hope this helps

6 0

3 years ago

Help me plz I’m struggling with this

elena-s [515]

Answer:

AC = 8√3 AC = 7.65

A = 43.17° AB = 16.8

B = 46.83° B = 27°

Step-by-step explanation:

FIRST TRIANGLE

by using pythagorus theorem:

Hypo² = Base² + height²

19² = 13² + AC²

AC² = 19² - 13²

AC² = 192

AC = √192

AC = 8√3

sinФ =base/hypo

sin A = 13/19

A = sin^-1 (13/19)

A = 43.17°

43.17°+ B + 90° =180 (sum of angles of triangle)

B = 180° - 133.17°

= 46.83°

<h3>SECOND TRIANGLE</h3>

TanФ = base/height

Tan 63° = 15 / AC

1.96 = 15/AC

AC = 15/1.96

AC = 7.65

AB² = AC² + BC²

AB² = 7.65² + 15²

AB² = 283.5

AB = √283.5

AB = 16.8

tan B = AC /BC

tanФ = 7.65/15

tanФ = 0.51

Ф = tan^-1(0.51)

B = 27°

3 0

3 years ago

11 POINTS PLZ HELP EMERGENCY

Bad White [126]

Part A

The given expression is:

$(-5(1+2i)+3i(3-4i)$

We expand to get:

$-5-10i+9i-12i^2$

Note that $i^2=-1$

$12-5-10i+9i$

$-5-10i+9i+12$

$7-i$

Part Bi)

The given expression is;

$\sqrt{-50}$

We simplify to get:

$\sqrt{25\times 2\times -1}$

$\sqrt{25\times} \sqr{2}\times \sqrt{-1}$

Note that:

$\sqrt{-1}=i$

$5\sqr{2}i$

This is now of the form $a+bi$ , where $a=0,b=5\sqr{2}$ .

This explains why it is a complex number;

Part bii)

The given expression is :

$\frac{\sqrt{-50} }{\sqrt{5}}$

We simplify to get

$\sqrt{\frac{-50 }{5}}$

$\sqrt{-25}$

$\sqrt{-25}=\sqrt{25}\times \sqrt{-1}$

$\sqrt{-25}=5\times i$

$\sqrt{-25}=5i$

Part C

We want to simplify:

$i^{22}$

We rewrite in terms of $i^2$

$i^{22}=(i^2)^{11}$

$i^{22}=(-1)^{11}$

$i^{22}=-11$

5 0

3 years ago