Solving for the missing term and the missing coefficient (6a − )5a = ( ) a^2 − 35a
Let the missing term be X
Let the missing coefficient be Y
Therefore, (6a – X)5a = Y(a^2) – 35a
6a x 5a – X.5a = Y.a^2 – 35a
30a^2 – X.5a = Y.a^2 – 35a
Equating co-efficients,
30a^2 = Y.a^2; X.5a = 35a
30 = Y; 5X = 35
Y = 30; X = 7
Therefore, (6a-7)5a = 30 a^2 – 35a
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Answer:
No, because as the x-values are increasing by a constant amount, the y-values are not being multiplied by a constant amount.
Step-by-step explanation:
We have a set of ordered pairs of the form (x, y)
If a function is exponential then the ratio between the consecutive values of y, is always equal to a constant.
This means that:
\frac{y_2}{y_1}=\frac{y_3}{y_2}=\frac{y_4}{y_3}=by1y2=y2y3=y3y4=b
This is: y_2=by_1y2=by1
Now we have this set of points {(-1, -5), (0, -3), (1, -1), (2, 1)}
Observe that:
\begin{gathered}\frac{y_2}{y_1}=\frac{-3}{-5}=\frac{3}{5}\\\\\frac{y_3}{y_2}=\frac{-1}{-3}=\frac{1}{3}\\\\\frac{3}{5}\neq \frac{1}{3}\end{gathered}y1y2=−5−3=53y2y3=−3−1=3153=31
Then the values of y are not multiplied by a constant amount "b"
(2x-1)(x+4)=0
Step-by-step explanation:
A random zero property of multiplication is taken to find the solution
(2x-1)(x+4)=0
consider a=2x-1 and b=x-4 a.b=0
either a or b or both must be 0
equating both the equations
2x-1=0 or x=4=0 x-4=0
2x-1=0 x=4
2x=1
x=1/2
substitute the values of x in the main equation
[2(1/2)-1][(1/2)+4]=0
4/17=x/100 》400\17=x 》x=23.5
The garden area is maximum when the enclosure is a square.
If a is the length of the side of the square then the length of the building is also a.
The perimeter length is 4a made up of 81+a feet, so 81+a=4a and 3a=81 making a=27 feet.
