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3 years ago

Which of the following is a monomial

Mathematics

2 answers:

4vir4ik [10]3 years ago

8 0

Answer:

A. 11x^2

Step-by-step explanation:

A. is correct because it has one term and is a polynomial.

anygoal [31]3 years ago

7 0

Answer: The correct answer is A. because it has only one term

* hope this helps!

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The rectangle below has an area of x^2+8x+15x

Darina [25.2K]

Answer:

The length of the rectangle is x+5.

Step-by-step explanation:

Given : The rectangle below has an area of $x^2+8x+15$ square meter and a width of $x+3$ meter.

To find : What expression represents the length of the rectangle?

Solution :

The area of the rectangle is given by,

$\text{Area}=\text{Length}\times \text{Breadth}$

$\text{Area}=x^2+8x+15$

$\text{Breadth}=x+3$

$x^2+8x+15=\text{Length}\times(x+3)$

$\text{Length}=\frac{x^2+8x+15}{x+3}$

$\text{Length}=\frac{(x+5)(x+3)}{x+3}$

$\text{Length}=x+5$

Therefore, the length of the rectangle is x+5.

7 0

3 years ago

Which is the equation of a circle that has a center of (-1, 3) and passes through the point (3, 6)?

Anna [14]

 the answer is 15. Hope this will help u.....

4 0

3 years ago

Read 2 more answers

Awnser this please i will give you 16

Aleks04 [339]

Answer:

Its EFBGCAHDI

4 0

2 years ago

What is the area of the trapezoid

irga5000 [103]

The equation for a trapezoid is A = a+b all over 2 times h

So, you would simply substitute.

A=15

B=12

H=8

15+12/2 (8)=

27/2 (8)=

13.5 (8)=

108.

6 0

3 years ago

Read 2 more answers

Elizabeth attempts a field goal by kicking a football from the ground with an initial vertical

sammy [17]

$\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{64}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{0\qquad \textit{from the ground}}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf h(t)=-16t^2+64t+0\implies h(t)=-16t^2+64t\implies \stackrel{\textit{hits the ground}~\hfill }{0=-16t^2+64t} \\\\\\ 0=-16t(t-4)\implies t= \begin{cases} 0\\ \boxed{4} \end{cases}$

Check the picture below, it hits the ground at 0 feet, where it came from, the ground, and when it came back down.

5 0

3 years ago