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IgorLugansk [536]
3 years ago
12

Common denominator between six and 44

Mathematics
1 answer:
Scilla [17]3 years ago
4 0

The Least Common Multiple of 6 and 44 is 132.

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If you're into anime could you answer and let me know? I'll be commenting 3 anime recommendations btw.
nikklg [1K]

1. My hero Academia

A show abt a boy who trains to become a good hero.

2. Haikyuu

A show abt a volleyball team who has a strong duo pair and makes it to nationals.

3. Hunter x Hunter

A show abt a boy who wants to become a hunter just so

he can go look for his dad.

These 3 shows are really good to start watching especially if you are just starting to watch anime. Good luck.

5 0
2 years ago
This package of cheese costs $2.97 (there are 11 slices of cheese)
torisob [31]

Answer:

$4.86

Step-by-step explanation:

2.97/11 =.27                 .27 x 18= 4.86

7 0
3 years ago
Read 2 more answers
mark had to place 1 penny in the first bag. he would place 2 pennies in the next bag, 4 pennies in the bag after that, and 8 pen
Aloiza [94]
Hehxbshdbsnejbdjshdhbsjshdhwbxbsh
5 0
3 years ago
Suppose N has a geometric distribution with parameter p. Derive a closed-form expression for E(N | N <= k), k = 1,2,... Check
vfiekz [6]

Answer:

P(X= k) = (1-p)^k-1.p

Step-by-step explanation:

Given that the number of trials is

N < = k, the geometric distribution gives the probability that there are k-1 trials that result in failure(F) before the success(S) at the kth trials.

Given p = success,

1 - p = failure

Hence the distribution is described as: Pr ( FFFF.....FS)

Pr(X= k) = (1-p)(1-p)(1-p)....(1-p)p

Pr((X=k) = (1 - p)^ (k-1) .p

Since N<=k

Pr (X =k) = p(1-p)^k-1, k= 1,2,...k

0, elsewhere

If the probability is defined for Y, the number of failure before a success

Pr (Y= k) = p(1-p)^y......k= 0,1,2,3

0, elsewhere.

Given p= 0.2, k= 3,

P(X= 3) =( 0.2) × (1 - 0.2)²

P(X=3) = 0.128

3 0
3 years ago
I will give brainliest answer
snow_tiger [21]

Step-by-step explanation:

inner region

A=πr^2

A=π*6^2

A=π*36cm^2

A=113.09cm^2

shaded region(outer)

A=πr^2

A=π*9^2

A=π*81cm^2

A=254.46cm^2

Area of shaded region=254.46cm^2-113.09cm^2

=141.37cm^2

Mark brianliest if my answer suit your question

5 0
3 years ago
Read 2 more answers
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