1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nuetrik [128]
3 years ago
15

Lf oil costs $95 per barrel and $1 =R8. How much does a barrel cost in rands?.​

Mathematics
1 answer:
Elan Coil [88]3 years ago
7 0

Answer:

R760

Step-by-step explanation:

If $1 is equivalent to R8 and the total oil costs $95 you must multiply 8x95. This leaves you with an answer of R760

You might be interested in
FILL IN THE BLANK
IgorLugansk [536]
Now, we know that he's charging $12 per session to each of his students, and he has 14 students currently, so his revenue is just 14 * 12 or 168 bucks.

now, let's take a peek as the session price goes up in jumps of 2, from 12, to 14, 16, 18 and so on, as each jumps happen, the students drop by 1, from 14, to 13, to 12 and so on.

\bf \begin{array}{ccccllll}
\stackrel{increase}{x}&\stackrel{new}{price}&students&\stackrel{revenue}{y}\\
------&------&------&------\\
0&12&14&168\\
1&14&13&182\\
2&16&12&192\\
3&18&11&198\\
\boxed{4}&20&10&\boxed{200}\\
5&22&9&198\\
6&24&8&192\\
7&26&7&182\\
8&28&6&168\\
..&..&..&..
\end{array}

notice, the revenue starts off at 168, goes up up, reaches 200 bucks and then starts to drop back down.

thus, that means the U-turn or vertex of that revenue function is at 4,200, namely h = 4, and k = 200

\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad  vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
\stackrel{c(x)}{y}=a(x-\stackrel{h}{4})\stackrel{k}{+200}
\\\\\\
\textit{now, we also know that }
\begin{cases}
x=2\\
y=192
\end{cases}\implies 192=a(2-4)^2+200
\\\\\\
-8=a(-2)^2\implies -8=4a\implies \cfrac{-8}{4}=a\implies -2=a
\\\\\\


\bf therefore\qquad \stackrel{ c(x)}{y}=-2(x-4)^2+200\impliedby \textit{let's expand that}
\\\\\\
y=-2(x^2-8x+16)+200\implies y=-2x^2+16x-32+200
\\\\\\
\stackrel{y}{c(x)}=-2x^2+16x+168
3 0
3 years ago
Read 2 more answers
Base ten numeral<br><br> What is Two and four hundred fifty eight thousandths?
Hunter-Best [27]

Answer:

2.458

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Please answer this question now in two minutes
kvv77 [185]

Answer:

m∠C = 102°

Step-by-step explanation:

This diagram is a Quadrilateral inscribed in a circle

The first step is to determine what m∠B

is

The sum of opposite angles in an inscribed quadrilateral is equal to 180°

m∠D + m∠B = 180°

m∠B = 180° - m∠D

m∠B = 180° - 80°

m∠B = 100°

Second step is we proceed to determine the exterior angles of the circle

m∠ADC = 2 × m∠B

m∠ADC = 2 × 100°

m∠ADC = 200°

m∠ADC = m∠CD + m∠AD

m∠AD = m∠ADC - m∠CD

m∠AD = 200° - 116°

m∠AD = 84°

The third step is to determine m∠BAD

m∠BAD = m∠AD + m∠AB

m∠BAD = 84° + 120°

m∠BAD = 204°

The final step Is to determine what m∠C is

It is important to note that:

m∠BAD is Opposite m∠C

Hence

m∠C = 1/2 × m∠BAD

m∠C = 1/2 × 204

m∠C = 102°

8 0
3 years ago
The breaking strengths of cables produced by a certain manufacturer have a mean, , of pounds, and a standard deviation of pounds
olchik [2.2K]

The question is incomplete. The complete question is :

The breaking strengths of cables produced by a certain manufacturer have a mean of 1900 pounds, and a standard deviation of 65 pounds. It is claimed that an improvement in the manufacturing process has increased the mean breaking strength. To evaluate this claim, 150 newly manufactured cables are randomly chosen and tested, and their mean breaking strength is found to be 1902 pounds. Assume that the population is normally distributed. Can we support, at the 0.01 level of significance, the claim that the mean breaking strength has increased?

Solution :

Given data :

Mean, μ = 1900

Standard deviation, σ = 65

Sample size, n = 150

Sample mean, $\overline x$ = 1902

Level of significance = 0.01

The hypothesis are :

$H_0 : \mu = 1900$

$H_1 : \mu > 1900$

Test statics :

We use the z test as the sample size is large and we know the population standard deviation.

$z=\frac{\overline x - \mu}{\sigma / \sqrt{n}}$

$z=\frac{1902-1900}{65 / \sqrt{150}}$

$z=\frac{2}{5.30723}$

$z=0.38$

Finding the p-value:

P-value = P(Z > z)

             = P(Z > 0.38)

             = 1 - P(Z < 0.38)

From the z table. we get

P(Z < 0.38) = 0.6480

Therefore,

P-value = 1 - P(Z < 0.38)

            = 1 - 0.6480

             = 0.3520

Decision :

If the p value is less than 0.01, then we reject the H_0, otherwise we fail to reject  H_0.

Since the value of p = 0.3520 > 0.01, the level of significance, then we fail to reject  H_0.

Conclusion :

At a significance level of 0.01, we have no sufficient evidence to support that the mean breaking strength has increased.

4 0
3 years ago
Which ordered pair would form a proportional relationship with the point graphed below
matrenka [14]
D (80,-30) so on so far
8 0
3 years ago
Read 2 more answers
Other questions:
  • What is the approximate base area of the resulting figure?<br> Area of a circle: A = πr2
    6·2 answers
  • NEED ANSWER DESPERATELY
    14·2 answers
  • What is the median of the data represented by the box plot?
    13·1 answer
  • Can you help with this problem!!
    5·1 answer
  • Find the volume of a cone. Either enter an exact answer in terms of or use 3.14 for pi and round your final answer to the neares
    5·1 answer
  • Identify the time being asked.
    6·2 answers
  • I need an answer for this
    13·2 answers
  • Please help me find the area
    6·1 answer
  • The temperature is 5° below zero the temperature falls 15° what is the temperature now
    7·1 answer
  • Someone help ill give brainliest to the person with an right answer!!!!!
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!