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3 years ago

Anyone know this please and thank you

Mathematics

1 answer:

Semmy [17]3 years ago

4 0

The graph shown is not a function because points (-1,2) and (-1,0) have the same x value.

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Find the length of a diagonal of a square with sides 10in. long

Ghella [55]

Hey!!!
Answer is....
diagonals of square bisect each other at right angles.
let diagonal be 2x
Using Pythagoras in a triangle enclosed by a side and 2 half diagonals...
${x}^{2} + {x}^{2} = {10}^{2}$
$2 {x}^{2} = 100$
${x }^{2} = 50$
$x = \sqrt{50}$
side of a diagonal=2 sqrt50
$= 10 \sqrt{2}$
cm......

HOPE IT HELPS YOU '_'

3 0

3 years ago

Read 2 more answers

15 POINTs_ NEED ASAP!

sleet_krkn [62]

Answer:

Step-by-step explanation:

1 TRUE

A number is always 100% Anyting bigger than 100% is going to be a bigger number

Anything smaller than 100% is a smaller number

2FALSE 5/100 = 0.05 and NOT 0.5

0.5% is the same as thalf of 100% = 50%

50/100 = 5/10 = 0.5

6 0

3 years ago

H(n)=-4n-5<br> g(n)=n-1<br> Find h(g(n)) =

Delicious77 [7]

Answer:

h(g(n))=4n-9

Step-by-step explanation:

h(g(n))=4*g(n)-5 ( we replace n in the formule of h(n) by g(n).

h(g(n))=4(n-1)-5

h(g(n))=4n-4-5

h(g(n))=4n-9

Hope you understand it

3 0

3 years ago

Determine which numbers could not be used to represent the probability of an event. Select all that apply. A. StartFraction 64 O

vova2212 [387]

Answer:

A. $\frac{64}{25}$ , because probability values cannot be greater than 1.

C. -1.5, because probability values cannot be less than 0.

Step-by-step explanation:

Probability is the extent to which an event is likely to happen. It ranges from 0(impossible) to 1(certain). Probability values can be written in decimal form or in fractional form.

The following numbers could not be used to represent the probability of an event.

A. $\frac{64}{25}$ , because probability values cannot be greater than 1.

C. -1.5, because probability values cannot be less than 0.

6 0

3 years ago

For what values of $x$ is $$\frac{x^2 + x + 3}{2x^2 + x - 6} \ge 0?$$ note: be thorough and explain why all points in your answe

Rus_ich [418]

To solve the inequality $\frac{x^2+x+3}{2x^2+x-6}\ge \:0$

$\mathrm{Factor\:the\:left\:hand\:side\:}\frac{x^2+x+3}{2x^2+x-6}:$

The numerator $x^2+x+3$ is not factorizable.

so factor the denominator $2x^2+x-6$ :

$2x^2+x-6=\left(2x^2-3x\right)+\left(4x-6\right)=x\left(2x-3\right)+2\left(2x-3\right)\\ \mathrm{Factor\:out\:}x\mathrm{\:from\:}2x^2-3x\mathrm{:\quad }x\left(2x-3\right)\\ \mathrm{Factor\:out\:}2\mathrm{\:from\:}4x-6\mathrm{:\quad }2\left(2x-3\right)\\$