S=d/t
45=29/t
t=45/29
convert to min
t=45/29 *60=38.66min
Answer:
I'd assume 7 times x, or 7x
Step-by-step explanation:
Algebraic phrases don’t include the equal sign and based on the information you gave me, I think 7x is the answer.
Answer:
See answer below
Step-by-step explanation:
The statement ‘x is an element of Y \X’ means, by definition of set difference, that "x is and element of Y and x is not an element of X", WIth the propositions given, we can rewrite this as "p∧¬q". Let us prove the identities given using the definitions of intersection, union, difference and complement. We will prove them by showing that the sets in both sides of the equation have the same elements.
i) x∈AnB if and only (if and only if means that both implications hold) x∈A and x∈B if and only if x∈A and x∉B^c (because B^c is the set of all elements that do not belong to X) if and only if x∈A\B^c. Then, if x∈AnB then x∈A\B^c, and if x∈A\B^c then x∈AnB. Thus both sets are equal.
ii) (I will abbreviate "if and only if" as "iff")
x∈A∪(B\A) iff x∈A or x∈B\A iff x∈A or x∈B and x∉A iff x∈A or x∈B (this is because if x∈B and x∈A then x∈A, so no elements are lost when we forget about the condition x∉A) iff x∈A∪B.
iii) x∈A\(B U C) iff x∈A and x∉B∪C iff x∈A and x∉B and x∉C (if x∈B or x∈C then x∈B∪C thus we cannot have any of those two options). iff x∈A and x∉B and x∈A and x∉C iff x∈(A\B) and x∈(A\B) iff x∈ (A\B) n (A\C).
iv) x∈A\(B ∩ C) iff x∈A and x∉B∩C iff x∈A and x∉B or x∉C (if x∈B and x∈C then x∈B∩C thus one of these two must be false) iff x∈A and x∉B or x∈A and x∉C iff x∈(A\B) or x∈(A\B) iff x∈ (A\B) ∪ (A\C).
Answer:
<em>x = 0.05</em>
<em>x = 1.57</em>
Step-by-step explanation:
The given equation is:
Moving all terms to the left side:
Now we define a function:
The solutions of the equation are the values of x such that y=0.
Since the function cannot be solved by algebraic methods, we use a graphing tool.
Those points where the graph crosses the x-axis are solutions of the equation.
Please refer to the graph in the figure below.
We can clearly identify there are two solutions at
x = 0.05
x = 1.57
Hello!
To find this out, figure out the amount of questions she got correct..
To get that number, multiply 96% as a decimal, (0.96) by 50.
0.96 * 50 = 48.
Turn 48 into fraction, (over 50)
48/50 is the answer.
Hope this helps!
