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GuDViN [60]
2 years ago
11

Bag A: Two thirds of the candies are yellow. What portion of the candies is green

Mathematics
1 answer:
dalvyx [7]2 years ago
7 0

Answer: \frac{1}{3} proportion of candies are green.  

Solution:  

In bag A, \frac{2}{3} candies are yellow.  

\frac{2}{3} this proportion shows ratio of favorable over total candies.  

Here numerator number is 2.  

So, Total number of yellow candies should be 2x

Total number of candies in Bag A would be 3x

Number of green candies in bag A = 3x-2x = x

Now we find the portion of green candies in bag A

\therefore,  \frac{x}{3x}

\frac{1}{3} portion of candies are green in bag A

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Troy started at the fire station. He walked to the library and then rode his bike to the post office. If Troy only traveled alon
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Answer:

Step-by-step explanation:

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So from the fire station you go 1 to the right and then 6 down, for a total of 7.  then from the library  it's 3 right then 4 up, which is 7 again.  7 to the first stop then 7 to the second makes 14 total.  

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3 years ago
In triangle abc, the perimeter is 36, and ab=ac. line ad is perpendicular to bc at the point d, and triangle abd's perimeter is
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Let x=ab=ac, and y=bc, and z=ad.

Since the perimeter of the triangle abc is 36, you have:

Perimeter of abc = 36
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The triangle is isosceles (it has two sides with equal length: ab and ac). The line perpendicular to the third side (bc) from the opposite vertex (a), divides that third side into two equal halves: the point d is the middle point of bc. This is a property of isosceles triangles, which is easily shown by similarity.

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So, we have two equations on x, y and z:

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(eq.2) 2x + y + 2z = 60

Substitute 2x + y by 36 from (eq.1) in (eq.2):

(eq.2') 36 + 2z = 60

And solve for z:

36 + 2z = 60 => 2z = 60 - 36 => 2z = 24 => z = 12

The measure of ad is 12.

If you prefer a less algebraic reasoning:

- The perimeter of abd is half the perimeter of abc plus the length of ad (since you have "cut" the triangle abc in two halves to obtain the triangle abd).

- Then, ad is the difference between the perimeter of abd and half the perimeter of abc:

ad = 30 - (36/2) = 30 - 18 = 12
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