Consider right triangle with vertices B - base of the hill, S - top of the statue and Y - you. In this triangle angle B is right and angle Y is 13.2°. If h is a height of the statue, then the legs YB and BS have lengths 77 ft and 16+h ft.
You have lengths of two legs and measure of one acute angle, then you can use tangent to find h:
ft.
Answer: the height of the statue is 2.0565 ft.
So each dimention is 32 by 8 by 10
so the surface area=2 times(8 times 10)+(2 times (32 times 10))+(2 times (8 times 32))=2 times 80+2 times 320+2 times 256=1312
if halved
just divide each by 2
(2 times 4 times 5)+(2 times 16 times 5)+(2 times 4 times 16)=(2 times 20)+(2 times 80)+(2 times 64)=40+160+128=328
the new surface area is 328 mm^2
I’m not sure but I’m guessing it could be 8 ft
Answer:
C. F(x) = x²
Step-by-step explanation:
"Quadratic" means "second degree". The only function with an exponent of 2 is choice C.
